You are given a 2D integer array ranges where ranges[i] = [starti, endi] denotes that all integers between starti and endi (both inclusive) are contained in the ith range.
You are to split ranges into two (possibly empty) groups such that:
Two ranges are said to be overlapping if there exists at least one integer that is present in both ranges.
\n\n[1, 3] and [2, 5] are overlapping because 2 and 3 occur in both ranges.Return the total number of ways to split ranges into two groups. Since the answer may be very large, return it modulo 109 + 7.
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Example 1:
\n\n\nInput: ranges = [[6,10],[5,15]]\nOutput: 2\nExplanation: \nThe two ranges are overlapping, so they must be in the same group.\nThus, there are two possible ways:\n- Put both the ranges together in group 1.\n- Put both the ranges together in group 2.\n\n\n
Example 2:
\n\n\nInput: ranges = [[1,3],[10,20],[2,5],[4,8]]\nOutput: 4\nExplanation: \nRanges [1,3], and [2,5] are overlapping. So, they must be in the same group.\nAgain, ranges [2,5] and [4,8] are also overlapping. So, they must also be in the same group. \nThus, there are four possible ways to group them:\n- All the ranges in group 1.\n- All the ranges in group 2.\n- Ranges [1,3], [2,5], and [4,8] in group 1 and [10,20] in group 2.\n- Ranges [1,3], [2,5], and [4,8] in group 2 and [10,20] in group 1.\n\n\n
\n
Constraints:
\n\n1 <= ranges.length <= 105ranges[i].length == 20 <= starti <= endi <= 109Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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