You are given a string s of lowercase English letters and a 2D integer array shifts where shifts[i] = [starti, endi, directioni]. For every i, shift the characters in s from the index starti to the index endi (inclusive) forward if directioni = 1, or shift the characters backward if directioni = 0.
Shifting a character forward means replacing it with the next letter in the alphabet (wrapping around so that 'z' becomes 'a'). Similarly, shifting a character backward means replacing it with the previous letter in the alphabet (wrapping around so that 'a' becomes 'z').
Return the final string after all such shifts to s are applied.
\n
Example 1:
\n\n\nInput: s = "abc", shifts = [[0,1,0],[1,2,1],[0,2,1]]\nOutput: "ace"\nExplanation: Firstly, shift the characters from index 0 to index 1 backward. Now s = "zac".\nSecondly, shift the characters from index 1 to index 2 forward. Now s = "zbd".\nFinally, shift the characters from index 0 to index 2 forward. Now s = "ace".\n\n
Example 2:
\n\n\nInput: s = "dztz", shifts = [[0,0,0],[1,1,1]]\nOutput: "catz"\nExplanation: Firstly, shift the characters from index 0 to index 0 backward. Now s = "cztz".\nFinally, shift the characters from index 1 to index 1 forward. Now s = "catz".\n\n\n
\n
Constraints:
\n\n1 <= s.length, shifts.length <= 5 * 104shifts[i].length == 30 <= starti <= endi < s.length0 <= directioni <= 1s consists of lowercase English letters.Compiled with clang 11 using the latest C++ 17 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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