{ "data": { "question": { "questionId": "1127", "questionFrontendId": "1046", "boundTopicId": null, "title": "Last Stone Weight", "titleSlug": "last-stone-weight", "content": "

You are given an array of integers stones where stones[i] is the weight of the ith stone.

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We are playing a game with the stones. On each turn, we choose the heaviest two stones and smash them together. Suppose the heaviest two stones have weights x and y with x <= y. The result of this smash is:

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At the end of the game, there is at most one stone left.

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Return the smallest possible weight of the left stone. If there are no stones left, return 0.

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Example 1:

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\nInput: stones = [2,7,4,1,8,1]\nOutput: 1\nExplanation: \nWe combine 7 and 8 to get 1 so the array converts to [2,4,1,1,1] then,\nwe combine 2 and 4 to get 2 so the array converts to [2,1,1,1] then,\nwe combine 2 and 1 to get 1 so the array converts to [1,1,1] then,\nwe combine 1 and 1 to get 0 so the array converts to [1] then that's the value of the last stone.\n
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Example 2:

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\nInput: stones = [1]\nOutput: 1\n
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Constraints:

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