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            "title": "Kth Smallest Product of Two Sorted Arrays",
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            "content": "Given two <strong>sorted 0-indexed</strong> integer arrays <code>nums1</code> and <code>nums2</code> as well as an integer <code>k</code>, return <em>the </em><code>k<sup>th</sup></code><em> (<strong>1-based</strong>) smallest product of </em><code>nums1[i] * nums2[j]</code><em> where </em><code>0 &lt;= i &lt; nums1.length</code><em> and </em><code>0 &lt;= j &lt; nums2.length</code>.\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [2,5], nums2 = [3,4], k = 2\n<strong>Output:</strong> 8\n<strong>Explanation:</strong> The 2 smallest products are:\n- nums1[0] * nums2[0] = 2 * 3 = 6\n- nums1[0] * nums2[1] = 2 * 4 = 8\nThe 2<sup>nd</sup> smallest product is 8.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [-4,-2,0,3], nums2 = [2,4], k = 6\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> The 6 smallest products are:\n- nums1[0] * nums2[1] = (-4) * 4 = -16\n- nums1[0] * nums2[0] = (-4) * 2 = -8\n- nums1[1] * nums2[1] = (-2) * 4 = -8\n- nums1[1] * nums2[0] = (-2) * 2 = -4\n- nums1[2] * nums2[0] = 0 * 2 = 0\n- nums1[2] * nums2[1] = 0 * 4 = 0\nThe 6<sup>th</sup> smallest product is 0.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [-2,-1,0,1,2], nums2 = [-3,-1,2,4,5], k = 3\n<strong>Output:</strong> -6\n<strong>Explanation:</strong> The 3 smallest products are:\n- nums1[0] * nums2[4] = (-2) * 5 = -10\n- nums1[0] * nums2[3] = (-2) * 4 = -8\n- nums1[4] * nums2[0] = 2 * (-3) = -6\nThe 3<sup>rd</sup> smallest product is -6.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums1.length, nums2.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>5</sup> &lt;= nums1[i], nums2[j] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= nums1.length * nums2.length</code></li>\n\t<li><code>nums1</code> and <code>nums2</code> are sorted.</li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    long long kthSmallestProduct(vector<int>& nums1, vector<int>& nums2, long long k) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def kthSmallestProduct(self, nums1, nums2, k):\n        \"\"\"\n        :type nums1: List[int]\n        :type nums2: List[int]\n        :type k: int\n        :rtype: int\n        \"\"\"\n        ",
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                    "code": "class Solution:\n    def kthSmallestProduct(self, nums1: List[int], nums2: List[int], k: int) -> int:\n        ",
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                    "code": "public class Solution {\n    public long KthSmallestProduct(int[] nums1, int[] nums2, long k) {\n        \n    }\n}",
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                    "code": "/**\n * @param {number[]} nums1\n * @param {number[]} nums2\n * @param {number} k\n * @return {number}\n */\nvar kthSmallestProduct = function(nums1, nums2, k) {\n    \n};",
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                    "code": "# @param {Integer[]} nums1\n# @param {Integer[]} nums2\n# @param {Integer} k\n# @return {Integer}\ndef kth_smallest_product(nums1, nums2, k)\n    \nend",
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                    "code": "class Solution {\n    fun kthSmallestProduct(nums1: IntArray, nums2: IntArray, k: Long): Long {\n        \n    }\n}",
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                    "code": "-spec kth_smallest_product(Nums1 :: [integer()], Nums2 :: [integer()], K :: integer()) -> integer().\nkth_smallest_product(Nums1, Nums2, K) ->\n  .",
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            "hints": [
                "Can we split this problem into four cases depending on the sign of the numbers?",
                "Can we binary search the value?"
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