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            "title": "Intersection of Two Arrays II",
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            "content": "<p>Given two integer arrays <code>nums1</code> and <code>nums2</code>, return <em>an array of their intersection</em>. Each element in the result must appear as many times as it shows in both arrays and you may return the result in <strong>any order</strong>.</p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [1,2,2,1], nums2 = [2,2]\n<strong>Output:</strong> [2,2]\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [4,9,5], nums2 = [9,4,9,8,4]\n<strong>Output:</strong> [4,9]\n<strong>Explanation:</strong> [9,4] is also accepted.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums1.length, nums2.length &lt;= 1000</code></li>\n\t<li><code>0 &lt;= nums1[i], nums2[i] &lt;= 1000</code></li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Follow up:</strong></p>\n\n<ul>\n\t<li>What if the given array is already sorted? How would you optimize your algorithm?</li>\n\t<li>What if <code>nums1</code>&#39;s size is small compared to <code>nums2</code>&#39;s size? Which algorithm is better?</li>\n\t<li>What if elements of <code>nums2</code> are stored on disk, and the memory is limited such that you cannot load all elements into the memory at once?</li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    vector<int> intersect(vector<int>& nums1, vector<int>& nums2) {\n        \n    }\n};",
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                    "code": "class Solution {\n    public int[] intersect(int[] nums1, int[] nums2) {\n        \n    }\n}",
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                    "code": "class Solution(object):\n    def intersect(self, nums1, nums2):\n        \"\"\"\n        :type nums1: List[int]\n        :type nums2: List[int]\n        :rtype: List[int]\n        \"\"\"\n        ",
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                    "code": "class Solution:\n    def intersect(self, nums1: List[int], nums2: List[int]) -> List[int]:\n        ",
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                    "code": "\n\n/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* intersect(int* nums1, int nums1Size, int* nums2, int nums2Size, int* returnSize){\n\n}",
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                    "code": "public class Solution {\n    public int[] Intersect(int[] nums1, int[] nums2) {\n        \n    }\n}",
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                    "code": "/**\n * @param {number[]} nums1\n * @param {number[]} nums2\n * @return {number[]}\n */\nvar intersect = function(nums1, nums2) {\n    \n};",
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                    "code": "# @param {Integer[]} nums1\n# @param {Integer[]} nums2\n# @return {Integer[]}\ndef intersect(nums1, nums2)\n    \nend",
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                    "code": "class Solution {\n    func intersect(_ nums1: [Int], _ nums2: [Int]) -> [Int] {\n        \n    }\n}",
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