You are given a 2D integer array coordinates and an integer k, where coordinates[i] = [xi, yi] are the coordinates of the ith point in a 2D plane.
We define the distance between two points (x1, y1) and (x2, y2) as (x1 XOR x2) + (y1 XOR y2) where XOR is the bitwise XOR operation.
Return the number of pairs (i, j) such that i < j and the distance between points i and j is equal to k.
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Example 1:
\n\n\nInput: coordinates = [[1,2],[4,2],[1,3],[5,2]], k = 5\nOutput: 2\nExplanation: We can choose the following pairs:\n- (0,1): Because we have (1 XOR 4) + (2 XOR 2) = 5.\n- (2,3): Because we have (1 XOR 5) + (3 XOR 2) = 5.\n\n\n
Example 2:
\n\n\nInput: coordinates = [[1,3],[1,3],[1,3],[1,3],[1,3]], k = 0\nOutput: 10\nExplanation: Any two chosen pairs will have a distance of 0. There are 10 ways to choose two pairs.\n\n\n
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Constraints:
\n\n2 <= coordinates.length <= 500000 <= xi, yi <= 1060 <= k <= 100x = x1 XOR x2 and y = y1 XOR y2 then we can get x2 = x XOR x1 and y2 = y XOR y1.x2 = x XOR x1 and y2 = (k - x) XOR y1.x and count the number of points (x1, x2) and (x2, y2).Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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