Given an integer array nums, return all the triplets [nums[i], nums[j], nums[k]] such that i != j, i != k, and j != k, and nums[i] + nums[j] + nums[k] == 0.
Notice that the solution set must not contain duplicate triplets.
\n\n\n
Example 1:
\n\n\nInput: nums = [-1,0,1,2,-1,-4]\nOutput: [[-1,-1,2],[-1,0,1]]\nExplanation: \nnums[0] + nums[1] + nums[2] = (-1) + 0 + 1 = 0.\nnums[1] + nums[2] + nums[4] = 0 + 1 + (-1) = 0.\nnums[0] + nums[3] + nums[4] = (-1) + 2 + (-1) = 0.\nThe distinct triplets are [-1,0,1] and [-1,-1,2].\nNotice that the order of the output and the order of the triplets does not matter.\n\n\n
Example 2:
\n\n\nInput: nums = [0,1,1]\nOutput: []\nExplanation: The only possible triplet does not sum up to 0.\n\n\n
Example 3:
\n\n\nInput: nums = [0,0,0]\nOutput: [[0,0,0]]\nExplanation: The only possible triplet sums up to 0.\n\n\n
\n
Constraints:
\n\n3 <= nums.length <= 3000-105 <= nums[i] <= 105Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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