{ "data": { "question": { "questionId": "2867", "questionFrontendId": "2750", "categoryTitle": "Algorithms", "boundTopicId": 2317489, "title": "Ways to Split Array Into Good Subarrays", "titleSlug": "ways-to-split-array-into-good-subarrays", "content": "

You are given a binary array nums.

\n\n

A subarray of an array is good if it contains exactly one element with the value 1.

\n\n

Return an integer denoting the number of ways to split the array nums into good subarrays. As the number may be too large, return it modulo 109 + 7.

\n\n

A subarray is a contiguous non-empty sequence of elements within an array.

\n\n

 

\n

Example 1:

\n\n
\nInput: nums = [0,1,0,0,1]\nOutput: 3\nExplanation: There are 3 ways to split nums into good subarrays:\n- [0,1] [0,0,1]\n- [0,1,0] [0,1]\n- [0,1,0,0] [1]\n
\n\n

Example 2:

\n\n
\nInput: nums = [0,1,0]\nOutput: 1\nExplanation: There is 1 way to split nums into good subarrays:\n- [0,1,0]\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "将数组划分成若干好子数组的方式", "translatedContent": "

给你一个二元数组 nums

\n\n

如果数组中的某个子数组 恰好 只存在 个值为 1 的元素,则认为该子数组是一个 好子数组

\n\n

请你统计将数组 nums 划分成若干 好子数组 的方法数,并以整数形式返回。由于数字可能很大,返回其对 109 + 7 取余 之后的结果。

\n\n

子数组是数组中的一个连续 非空 元素序列。

\n\n

 

\n\n

示例 1:

\n\n
输入:nums = [0,1,0,0,1]\n输出:3\n解释:存在 3 种可以将 nums 划分成若干好子数组的方式:\n- [0,1] [0,0,1]\n- [0,1,0] [0,1]\n- [0,1,0,0] [1]\n
\n\n

示例 2:

\n\n
输入:nums = [0,1,0]\n输出:1\n解释:存在 1 种可以将 nums 划分成若干好子数组的方式:\n- [0,1,0]\n
\n\n

 

\n\n

提示:

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"JavaScript", "langSlug": "javascript", "code": "/**\n * @param {number[]} nums\n * @return {number}\n */\nvar numberOfGoodSubarraySplits = function(nums) {\n\n};", "__typename": "CodeSnippetNode" }, { "lang": "TypeScript", "langSlug": "typescript", "code": "function numberOfGoodSubarraySplits(nums: number[]): number {\n\n};", "__typename": "CodeSnippetNode" }, { "lang": "PHP", "langSlug": "php", "code": "class Solution {\n\n /**\n * @param Integer[] $nums\n * @return Integer\n */\n function numberOfGoodSubarraySplits($nums) {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Swift", "langSlug": "swift", "code": "class Solution {\n func numberOfGoodSubarraySplits(_ nums: [Int]) -> Int {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Kotlin", "langSlug": "kotlin", "code": "class Solution {\n fun numberOfGoodSubarraySplits(nums: IntArray): Int {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Dart", "langSlug": "dart", "code": "class Solution {\n int numberOfGoodSubarraySplits(List nums) {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Go", "langSlug": "golang", "code": "func numberOfGoodSubarraySplits(nums []int) int {\n\n}", "__typename": "CodeSnippetNode" }, { "lang": "Ruby", "langSlug": "ruby", "code": "# @param {Integer[]} nums\n# @return {Integer}\ndef number_of_good_subarray_splits(nums)\n\nend", "__typename": "CodeSnippetNode" }, { "lang": "Scala", "langSlug": "scala", "code": "object Solution {\n def numberOfGoodSubarraySplits(nums: Array[Int]): Int = {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Rust", "langSlug": "rust", "code": "impl Solution {\n pub fn number_of_good_subarray_splits(nums: Vec) -> i32 {\n\n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Racket", "langSlug": "racket", "code": "(define/contract (number-of-good-subarray-splits nums)\n (-> (listof exact-integer?) exact-integer?)\n\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec 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