You are given a 0-indexed integer array nums of size n, and a 0-indexed integer array pattern of size m consisting of integers -1, 0, and 1.
A subarray nums[i..j] of size m + 1 is said to match the pattern if the following conditions hold for each element pattern[k]:
nums[i + k + 1] > nums[i + k] if pattern[k] == 1.nums[i + k + 1] == nums[i + k] if pattern[k] == 0.nums[i + k + 1] < nums[i + k] if pattern[k] == -1.Return the count of subarrays in nums that match the pattern.
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Example 1:
\n\n\nInput: nums = [1,2,3,4,5,6], pattern = [1,1]\nOutput: 4\nExplanation: The pattern [1,1] indicates that we are looking for strictly increasing subarrays of size 3. In the array nums, the subarrays [1,2,3], [2,3,4], [3,4,5], and [4,5,6] match this pattern.\nHence, there are 4 subarrays in nums that match the pattern.\n\n\n
Example 2:
\n\n\nInput: nums = [1,4,4,1,3,5,5,3], pattern = [1,0,-1]\nOutput: 2\nExplanation: Here, the pattern [1,0,-1] indicates that we are looking for a sequence where the first number is smaller than the second, the second is equal to the third, and the third is greater than the fourth. In the array nums, the subarrays [1,4,4,1], and [3,5,5,3] match this pattern.\nHence, there are 2 subarrays in nums that match the pattern.\n\n\n
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Constraints:
\n\n2 <= n == nums.length <= 1061 <= nums[i] <= 1091 <= m == pattern.length < n-1 <= pattern[i] <= 1给你一个下标从 0 开始长度为 n 的整数数组 nums ，和一个下标从 0 开始长度为 m 的整数数组 pattern ，pattern 数组只包含整数 -1 ，0 和 1 。
大小为 m + 1 的子数组 nums[i..j] 如果对于每个元素 pattern[k] 都满足以下条件，那么我们说这个子数组匹配模式数组 pattern ：
pattern[k] == 1 ，那么 nums[i + k + 1] > nums[i + k]pattern[k] == 0 ，那么 nums[i + k + 1] == nums[i + k]pattern[k] == -1 ，那么 nums[i + k + 1] < nums[i + k]请你返回匹配 pattern 的 nums 子数组的 数目 。
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示例 1：
\n\n\n输入：nums = [1,2,3,4,5,6], pattern = [1,1]\n输出：4\n解释：模式 [1,1] 说明我们要找的子数组是长度为 3 且严格上升的。在数组 nums 中，子数组 [1,2,3] ，[2,3,4] ，[3,4,5] 和 [4,5,6] 都匹配这个模式。\n所以 nums 中总共有 4 个子数组匹配这个模式。\n\n\n
示例 2：
\n\n\n输入：nums = [1,4,4,1,3,5,5,3], pattern = [1,0,-1]\n输出：2\n解释：这里，模式数组 [1,0,-1] 说明我们需要找的子数组中，第一个元素小于第二个元素，第二个元素等于第三个元素，第三个元素大于第四个元素。在 nums 中，子数组 [1,4,4,1] 和 [3,5,5,3] 都匹配这个模式。\n所以 nums 中总共有 2 个子数组匹配这个模式。\n\n\n
\n\n
提示：
\n\n2 <= n == nums.length <= 1061 <= nums[i] <= 1091 <= m == pattern.length < n-1 <= pattern[i] <= 1nums2 such that nums2[i] = 1 if nums[i + 1] > nums[i], nums2[i] = 0 if nums[i + 1] == nums[i], and nums2[i] = -1 if nums[i + 1] < nums[i].",
"The problem becomes: “Count the number of subarrays in nums2 that are equal to pattern.",
"Use Knuth-Morris-Pratt or Z-Function algorithms."
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