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            "questionId": "2095",
            "questionFrontendId": "1963",
            "categoryTitle": "Algorithms",
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            "title": "Minimum Number of Swaps to Make the String Balanced",
            "titleSlug": "minimum-number-of-swaps-to-make-the-string-balanced",
            "content": "<p>You are given a <strong>0-indexed</strong> string <code>s</code> of <strong>even</strong> length <code>n</code>. The string consists of <strong>exactly</strong> <code>n / 2</code> opening brackets <code>&#39;[&#39;</code> and <code>n / 2</code> closing brackets <code>&#39;]&#39;</code>.</p>\n\n<p>A string is called <strong>balanced</strong> if and only if:</p>\n\n<ul>\n\t<li>It is the empty string, or</li>\n\t<li>It can be written as <code>AB</code>, where both <code>A</code> and <code>B</code> are <strong>balanced</strong> strings, or</li>\n\t<li>It can be written as <code>[C]</code>, where <code>C</code> is a <strong>balanced</strong> string.</li>\n</ul>\n\n<p>You may swap the brackets at <strong>any</strong> two indices <strong>any</strong> number of times.</p>\n\n<p>Return <em>the <strong>minimum</strong> number of swaps to make </em><code>s</code> <em><strong>balanced</strong></em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;][][&quot;\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> You can make the string balanced by swapping index 0 with index 3.\nThe resulting string is &quot;[[]]&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;]]][[[&quot;\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> You can do the following to make the string balanced:\n- Swap index 0 with index 4. s = &quot;[]][][&quot;.\n- Swap index 1 with index 5. s = &quot;[[][]]&quot;.\nThe resulting string is &quot;[[][]]&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;[]&quot;\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> The string is already balanced.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == s.length</code></li>\n\t<li><code>2 &lt;= n &lt;= 10<sup>6</sup></code></li>\n\t<li><code>n</code> is even.</li>\n\t<li><code>s[i]</code> is either <code>&#39;[&#39; </code>or <code>&#39;]&#39;</code>.</li>\n\t<li>The number of opening brackets <code>&#39;[&#39;</code> equals <code>n / 2</code>, and the number of closing brackets <code>&#39;]&#39;</code> equals <code>n / 2</code>.</li>\n</ul>\n",
            "translatedTitle": "使字符串平衡的最小交换次数",
            "translatedContent": "<p>给你一个字符串 <code>s</code> ，<strong>下标从 0 开始</strong> ，且长度为偶数 <code>n</code> 。字符串 <strong>恰好</strong> 由 <code>n / 2</code> 个开括号 <code>'['</code> 和 <code>n / 2</code> 个闭括号 <code>']'</code> 组成。</p>\n\n<p>只有能满足下述所有条件的字符串才能称为 <strong>平衡字符串</strong> ：</p>\n\n<ul>\n\t<li>字符串是一个空字符串，或者</li>\n\t<li>字符串可以记作 <code>AB</code> ，其中 <code>A</code> 和 <code>B</code> 都是 <strong>平衡字符串</strong> ，或者</li>\n\t<li>字符串可以写成 <code>[C]</code> ，其中 <code>C</code> 是一个 <strong>平衡字符串</strong> 。</li>\n</ul>\n\n<p>你可以交换 <strong>任意</strong> 两个下标所对应的括号 <strong>任意</strong> 次数。</p>\n\n<p>返回使<em> </em><code>s</code> 变成 <strong>平衡字符串</strong> 所需要的 <strong>最小</strong> 交换次数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"][][\"\n<strong>输出：</strong>1\n<strong>解释：</strong>交换下标 0 和下标 3 对应的括号，可以使字符串变成平衡字符串。\n最终字符串变成 \"[[]]\" 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"]]][[[\"\n<strong>输出：</strong>2\n<strong>解释：</strong>执行下述操作可以使字符串变成平衡字符串：\n- 交换下标 0 和下标 4 对应的括号，s = \"[]][][\" 。\n- 交换下标 1 和下标 5 对应的括号，s = \"[[][]]\" 。\n最终字符串变成 \"[[][]]\" 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"[]\"\n<strong>输出：</strong>0\n<strong>解释：</strong>这个字符串已经是平衡字符串。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == s.length</code></li>\n\t<li><code>2 &lt;= n &lt;= 10<sup>6</sup></code></li>\n\t<li><code>n</code> 为偶数</li>\n\t<li><code>s[i]</code> 为<code>'['</code> 或 <code>']'</code></li>\n\t<li>开括号 <code>'['</code> 的数目为 <code>n / 2</code> ，闭括号 <code>']'</code> 的数目也是 <code>n / 2</code></li>\n</ul>\n",
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