You are given a 0-indexed integer array nums and an integer p. Find p pairs of indices of nums such that the maximum difference amongst all the pairs is minimized. Also, ensure no index appears more than once amongst the p pairs.
Note that for a pair of elements at the index i and j, the difference of this pair is |nums[i] - nums[j]|, where |x| represents the absolute value of x.
Return the minimum maximum difference among all p pairs. We define the maximum of an empty set to be zero.
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Example 1:
\n\n\nInput: nums = [10,1,2,7,1,3], p = 2\nOutput: 1\nExplanation: The first pair is formed from the indices 1 and 4, and the second pair is formed from the indices 2 and 5. \nThe maximum difference is max(|nums[1] - nums[4]|, |nums[2] - nums[5]|) = max(0, 1) = 1. Therefore, we return 1.\n\n\n
Example 2:
\n\n\nInput: nums = [4,2,1,2], p = 1\nOutput: 0\nExplanation: Let the indices 1 and 3 form a pair. The difference of that pair is |2 - 2| = 0, which is the minimum we can attain.\n\n\n
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Constraints:
\n\n1 <= nums.length <= 1050 <= nums[i] <= 1090 <= p <= (nums.length)/2给你一个下标从 0 开始的整数数组 nums 和一个整数 p 。请你从 nums 中找到 p 个下标对，每个下标对对应数值取差值，你需要使得这 p 个差值的 最大值 最小。同时，你需要确保每个下标在这 p 个下标对中最多出现一次。
对于一个下标对 i 和 j ，这一对的差值为 |nums[i] - nums[j]| ，其中 |x| 表示 x 的 绝对值 。
请你返回 p 个下标对对应数值 最大差值 的 最小值 。
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示例 1：
\n\n\n输入：nums = [10,1,2,7,1,3], p = 2\n输出：1\n解释：第一个下标对选择 1 和 4 ，第二个下标对选择 2 和 5 。\n最大差值为 max(|nums[1] - nums[4]|, |nums[2] - nums[5]|) = max(0, 1) = 1 。所以我们返回 1 。\n\n\n
示例 2：
\n\n\n输入：nums = [4,2,1,2], p = 1\n输出：0\n解释：选择下标 1 和 3 构成下标对。差值为 |2 - 2| = 0 ，这是最大差值的最小值。\n\n\n
\n\n
提示：
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