{ "data": { "question": { "questionId": "2184", "questionFrontendId": "2060", "categoryTitle": "Algorithms", "boundTopicId": 1072345, "title": "Check if an Original String Exists Given Two Encoded Strings", "titleSlug": "check-if-an-original-string-exists-given-two-encoded-strings", "content": "
An original string, consisting of lowercase English letters, can be encoded by the following steps:
\n\nFor example, one way to encode an original string "abcdefghijklmnop"
might be:
["ab", "cdefghijklmn", "o", "p"]
.["ab", "12", "1", "p"]
."ab121p"
.Given two encoded strings s1
and s2
, consisting of lowercase English letters and digits 1-9
(inclusive), return true
if there exists an original string that could be encoded as both s1
and s2
. Otherwise, return false
.
Note: The test cases are generated such that the number of consecutive digits in s1
and s2
does not exceed 3
.
\n
Example 1:
\n\n\nInput: s1 = "internationalization", s2 = "i18n"\nOutput: true\nExplanation: It is possible that "internationalization" was the original string.\n- "internationalization" \n -> Split: ["internationalization"]\n -> Do not replace any element\n -> Concatenate: "internationalization", which is s1.\n- "internationalization"\n -> Split: ["i", "nternationalizatio", "n"]\n -> Replace: ["i", "18", "n"]\n -> Concatenate: "i18n", which is s2\n\n\n
Example 2:
\n\n\nInput: s1 = "l123e", s2 = "44"\nOutput: true\nExplanation: It is possible that "leetcode" was the original string.\n- "leetcode" \n -> Split: ["l", "e", "et", "cod", "e"]\n -> Replace: ["l", "1", "2", "3", "e"]\n -> Concatenate: "l123e", which is s1.\n- "leetcode" \n -> Split: ["leet", "code"]\n -> Replace: ["4", "4"]\n -> Concatenate: "44", which is s2.\n\n\n
Example 3:
\n\n\nInput: s1 = "a5b", s2 = "c5b"\nOutput: false\nExplanation: It is impossible.\n- The original string encoded as s1 must start with the letter 'a'.\n- The original string encoded as s2 must start with the letter 'c'.\n\n\n
\n
Constraints:
\n\n1 <= s1.length, s2.length <= 40
s1
and s2
consist of digits 1-9
(inclusive), and lowercase English letters only.s1
and s2
does not exceed 3
.原字符串由小写字母组成,可以按下述步骤编码:
\n\n例如,编码 \"abcdefghijklmnop\"
的一种方法可以描述为:
[\"ab\", \"cdefghijklmn\", \"o\", \"p\"]
。[\"ab\", \"12\", \"1\", \"p\"]
。\"ab121p\"
。给你两个编码后的字符串 s1
和 s2
,由小写英文字母和数字 1-9
组成。如果存在能够同时编码得到 s1
和 s2
原字符串,返回 true
;否则,返回 false
。
注意:生成的测试用例满足 s1
和 s2
中连续数字数不超过 3
。
\n\n
示例 1:
\n\n输入:s1 = \"internationalization\", s2 = \"i18n\"\n输出:true\n解释:\"internationalization\" 可以作为原字符串\n- \"internationalization\" \n -> 分割: [\"internationalization\"]\n -> 不替换任何元素\n -> 连接: \"internationalization\",得到 s1\n- \"internationalization\"\n -> 分割: [\"i\", \"nternationalizatio\", \"n\"]\n -> 替换: [\"i\", \"18\", \"n\"]\n -> 连接: \"i18n\",得到 s2\n\n\n
示例 2:
\n\n输入:s1 = \"l123e\", s2 = \"44\"\n输出:true\n解释:\"leetcode\" 可以作为原字符串\n- \"leetcode\" \n -> 分割: [\"l\", \"e\", \"et\", \"cod\", \"e\"]\n -> 替换: [\"l\", \"1\", \"2\", \"3\", \"e\"]\n -> 连接: \"l123e\",得到 s1\n- \"leetcode\" \n -> 分割: [\"leet\", \"code\"]\n -> 替换: [\"4\", \"4\"]\n -> 连接: \"44\",得到 s2\n\n\n
示例 3:
\n\n输入:s1 = \"a5b\", s2 = \"c5b\"\n输出:false\n解释:不存在这样的原字符串\n- 编码为 s1 的字符串必须以字母 'a' 开头\n- 编码为 s2 的字符串必须以字母 'c' 开头\n\n\n
示例 4:
\n\n输入:s1 = \"112s\", s2 = \"g841\"\n输出:true\n解释:\"gaaaaaaaaaaaas\" 可以作为原字符串\n- \"gaaaaaaaaaaaas\"\n -> 分割: [\"g\", \"aaaaaaaaaaaa\", \"s\"]\n -> 替换: [\"1\", \"12\", \"s\"]\n -> 连接: \"112s\",得到 s1\n- \"gaaaaaaaaaaaas\"\n -> 分割: [\"g\", \"aaaaaaaa\", \"aaaa\", \"s\"]\n -> 替换: [\"g\", \"8\", \"4\", \"1\"]\n -> 连接 \"g841\",得到 s2\n\n\n
示例 5:
\n\n输入:s1 = \"ab\", s2 = \"a2\"\n输出:false\n解释:不存在这样的原字符串\n- 编码为 s1 的字符串由两个字母组成\n- 编码为 s2 的字符串由三个字母组成\n\n\n
\n\n
提示:
\n\n1 <= s1.length, s2.length <= 40
s1
和 s2
仅由数字 1-9
和小写英文字母组成s1
和 s2
中连续数字数不超过 3
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