You are given a 0-indexed 2D matrix grid of size m x n, where (r, c) represents:
grid[r][c] = 0, orgrid[r][c] fish, if grid[r][c] > 0.A fisher can start at any water cell (r, c) and can do the following operations any number of times:
(r, c), orReturn the maximum number of fish the fisher can catch if he chooses his starting cell optimally, or 0 if no water cell exists.
An adjacent cell of the cell (r, c), is one of the cells (r, c + 1), (r, c - 1), (r + 1, c) or (r - 1, c) if it exists.
\n
Example 1:
\n![\"\"](\"https://assets.leetcode.com/uploads/2023/03/29/example.png\")
\n\nInput: grid = [[0,2,1,0],[4,0,0,3],[1,0,0,4],[0,3,2,0]]\nOutput: 7\nExplanation: The fisher can start at cell\n\n(1,3)and collect 3 fish, then move to cell(2,3)and collect 4 fish.\n
Example 2:
\n![\"\"](\"https://assets.leetcode.com/uploads/2023/03/29/example2.png\")
\n\nInput: grid = [[1,0,0,0],[0,0,0,0],[0,0,0,0],[0,0,0,1]]\nOutput: 1\nExplanation: The fisher can start at cells (0,0) or (3,3) and collect a single fish. \n\n\n
\n
Constraints:
\n\nm == grid.lengthn == grid[i].length1 <= m, n <= 100 <= grid[i][j] <= 10Compiled with clang 11 using the latest C++ 17 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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