{ "data": { "question": { "questionId": "3080", "questionFrontendId": "2871", "categoryTitle": "Algorithms", "boundTopicId": 2463047, "title": "Split Array Into Maximum Number of Subarrays", "titleSlug": "split-array-into-maximum-number-of-subarrays", "content": "

You are given an array nums consisting of non-negative integers.

\n\n

We define the score of subarray nums[l..r] such that l <= r as nums[l] AND nums[l + 1] AND ... AND nums[r] where AND is the bitwise AND operation.

\n\n

Consider splitting the array into one or more subarrays such that the following conditions are satisfied:

\n\n\n\n

Return the maximum number of subarrays in a split that satisfies the conditions above.

\n\n

A subarray is a contiguous part of an array.

\n\n

 

\n

Example 1:

\n\n
\nInput: nums = [1,0,2,0,1,2]\nOutput: 3\nExplanation: We can split the array into the following subarrays:\n- [1,0]. The score of this subarray is 1 AND 0 = 0.\n- [2,0]. The score of this subarray is 2 AND 0 = 0.\n- [1,2]. The score of this subarray is 1 AND 2 = 0.\nThe sum of scores is 0 + 0 + 0 = 0, which is the minimum possible score that we can obtain.\nIt can be shown that we cannot split the array into more than 3 subarrays with a total score of 0. So we return 3.\n
\n\n

Example 2:

\n\n
\nInput: nums = [5,7,1,3]\nOutput: 1\nExplanation: We can split the array into one subarray: [5,7,1,3] with a score of 1, which is the minimum possible score that we can obtain.\nIt can be shown that we cannot split the array into more than 1 subarray with a total score of 1. So we return 1.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "将数组分割成最多数目的子数组", "translatedContent": "

给你一个只包含 非负 整数的数组 nums 。

\n\n

我们定义满足 l <= r 的子数组 nums[l..r] 的分数为 nums[l] AND nums[l + 1] AND ... AND nums[r] ,其中 AND 是按位与运算。

\n\n

请你将数组分割成一个或者更多子数组,满足:

\n\n\n\n

请你在满足以上要求的条件下,返回 最多 可以得到多少个子数组。

\n\n

一个 子数组 是一个数组中一段连续的元素。

\n\n

 

\n\n

示例 1:

\n\n
\n输入:nums = [1,0,2,0,1,2]\n输出:3\n解释:我们可以将数组分割成以下子数组:\n- [1,0] 。子数组分数为 1 AND 0 = 0 。\n- [2,0] 。子数组分数为 2 AND 0 = 0 。\n- [1,2] 。子数组分数为 1 AND 2 = 0 。\n分数之和为 0 + 0 + 0 = 0 ,是我们可以得到的最小分数之和。\n在分数之和为 0 的前提下,最多可以将数组分割成 3 个子数组。所以返回 3 。\n
\n\n

示例 2:

\n\n
\n输入:nums = [5,7,1,3]\n输出:1\n解释:我们可以将数组分割成一个子数组:[5,7,1,3] ,分数为 1 ,这是可以得到的最小总分数。\n在总分数为 1 的前提下,最多可以将数组分割成 1 个子数组。所以返回 1 。\n
\n\n

 

\n\n

提示:

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nums) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "JavaScript", "langSlug": "javascript", "code": "/**\n * @param {number[]} nums\n * @return {number}\n */\nvar maxSubarrays = function(nums) {\n \n};", "__typename": "CodeSnippetNode" }, { "lang": "TypeScript", "langSlug": "typescript", "code": "function maxSubarrays(nums: number[]): number {\n \n};", "__typename": "CodeSnippetNode" }, { "lang": "PHP", "langSlug": "php", "code": "class Solution {\n\n /**\n * @param Integer[] $nums\n * @return Integer\n */\n function maxSubarrays($nums) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Swift", "langSlug": "swift", "code": "class Solution {\n func maxSubarrays(_ nums: [Int]) -> Int {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Kotlin", "langSlug": "kotlin", "code": "class Solution {\n fun maxSubarrays(nums: IntArray): Int {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Dart", "langSlug": "dart", "code": "class Solution {\n int maxSubarrays(List nums) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Go", "langSlug": "golang", "code": "func maxSubarrays(nums []int) int {\n \n}", "__typename": "CodeSnippetNode" }, { "lang": "Ruby", "langSlug": "ruby", "code": "# @param {Integer[]} nums\n# @return {Integer}\ndef max_subarrays(nums)\n \nend", "__typename": "CodeSnippetNode" }, { "lang": "Scala", "langSlug": "scala", "code": "object Solution {\n def maxSubarrays(nums: Array[Int]): Int = {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Rust", "langSlug": "rust", "code": "impl Solution {\n pub fn max_subarrays(nums: Vec) -> i32 {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Racket", "langSlug": "racket", "code": "(define/contract (max-subarrays nums)\n (-> (listof exact-integer?) exact-integer?)\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec max_subarrays(Nums :: [integer()]) -> integer().\nmax_subarrays(Nums) ->\n .", 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