{ "data": { "question": { "questionId": "3591", "questionFrontendId": "3361", "categoryTitle": "Algorithms", "boundTopicId": 2997029, "title": "Shift Distance Between Two Strings", "titleSlug": "shift-distance-between-two-strings", "content": "
You are given two strings s
and t
of the same length, and two integer arrays nextCost
and previousCost
.
In one operation, you can pick any index i
of s
, and perform either one of the following actions:
s[i]
to the next letter in the alphabet. If s[i] == 'z'
, you should replace it with 'a'
. This operation costs nextCost[j]
where j
is the index of s[i]
in the alphabet.s[i]
to the previous letter in the alphabet. If s[i] == 'a'
, you should replace it with 'z'
. This operation costs previousCost[j]
where j
is the index of s[i]
in the alphabet.The shift distance is the minimum total cost of operations required to transform s
into t
.
Return the shift distance from s
to t
.
\n
Example 1:
\n\nInput: s = "abab", t = "baba", nextCost = [100,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0], previousCost = [1,100,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
\n\nOutput: 2
\n\nExplanation:
\n\ni = 0
and shift s[0]
25 times to the previous character for a total cost of 1.i = 1
and shift s[1]
25 times to the next character for a total cost of 0.i = 2
and shift s[2]
25 times to the previous character for a total cost of 1.i = 3
and shift s[3]
25 times to the next character for a total cost of 0.Example 2:
\n\nInput: s = "leet", t = "code", nextCost = [1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1], previousCost = [1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1]
\n\nOutput: 31
\n\nExplanation:
\n\ni = 0
and shift s[0]
9 times to the previous character for a total cost of 9.i = 1
and shift s[1]
10 times to the next character for a total cost of 10.i = 2
and shift s[2]
1 time to the previous character for a total cost of 1.i = 3
and shift s[3]
11 times to the next character for a total cost of 11.\n
Constraints:
\n\n1 <= s.length == t.length <= 105
s
and t
consist only of lowercase English letters.nextCost.length == previousCost.length == 26
0 <= nextCost[i], previousCost[i] <= 109
给你两个长度相同的字符串 s
和 t
,以及两个整数数组 nextCost
和 previousCost
。
一次操作中,你可以选择 s
中的一个下标 i
,执行以下操作 之一 :
s[i]
切换为字母表中的下一个字母,如果 s[i] == 'z'
,切换后得到 'a'
。操作的代价为 nextCost[j]
,其中 j
表示 s[i]
在字母表中的下标。s[i]
切换为字母表中的上一个字母,如果 s[i] == 'a'
,切换后得到 'z'
。操作的代价为 previousCost[j]
,其中 j
是 s[i]
在字母表中的下标。切换距离 指的是将字符串 s
变为字符串 t
的 最少 操作代价总和。
请你返回从 s
到 t
的 切换距离 。
\n\n
示例 1:
\n\n输入:s = \"abab\", t = \"baba\", nextCost = [100,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0], previousCost = [1,100,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
\n\n输出:2
\n\n解释:
\n\ni = 0
并将 s[0]
向前切换 25 次,总代价为 1 。i = 1
并将 s[1]
向后切换 25 次,总代价为 0 。i = 2
并将 s[2]
向前切换 25 次,总代价为 1 。i = 3
并将 s[3]
向后切换 25 次,总代价为 0 。示例 2:
\n\n输入:s = \"leet\", t = \"code\", nextCost = [1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1], previousCost = [1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1]
\n\n输出:31
\n\n解释:
\n\ni = 0
并将 s[0]
向前切换 9 次,总代价为 9 。i = 1
并将 s[1]
向后切换 10 次,总代价为 10 。i = 2
并将 s[2]
向前切换 1 次,总代价为 1 。i = 3
并将 s[3]
向后切换 11 次,总代价为 11 。\n\n
提示:
\n\n1 <= s.length == t.length <= 105
s
和 t
都只包含小写英文字母。nextCost.length == previousCost.length == 26
0 <= nextCost[i], previousCost[i] <= 109
(a, b)
, the cost of turning a
into b
is equal to the minimum between: \r\ni < j
, nextCost[i] + nextCost[i + 1] + … + nextCost[j - 1]
, and nextCost[i] + nextCost[i + 1] + … + nextCost[25] + nextCost[0] + … + nextCost[j - 1]
otherwise.i < j
, prevCost[i] + prevCost[i - 1] + … + prevCost[0] + prevCost[25] + … + prevCost[j + 1]
, and prevCost[i] + prevCost[i - 1] + … + prevCost[j + 1]
otherwise.i
and j
are the indices of a
and b
in the alphabet.",
"The shift distance is the sum of costs of turning s[i]
into t[i]
."
],
"solution": null,
"status": null,
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