You are given an m x n binary matrix grid.
A move consists of choosing any row or column and toggling each value in that row or column (i.e., changing all 0's to 1's, and all 1's to 0's).
Every row of the matrix is interpreted as a binary number, and the score of the matrix is the sum of these numbers.
\n\nReturn the highest possible score after making any number of moves (including zero moves).
\n\n\n
Example 1:
\n![\"\"](\"https://assets.leetcode.com/uploads/2021/07/23/lc-toogle1.jpg\")
\n\nInput: grid = [[0,0,1,1],[1,0,1,0],[1,1,0,0]]\nOutput: 39\nExplanation: 0b1111 + 0b1001 + 0b1111 = 15 + 9 + 15 = 39\n\n\n
Example 2:
\n\n\nInput: grid = [[0]]\nOutput: 1\n\n\n
\n
Constraints:
\n\nm == grid.lengthn == grid[i].length1 <= m, n <= 20grid[i][j] is either 0 or 1.给你一个大小为 m x n 的二元矩阵 grid ，矩阵中每个元素的值为 0 或 1 。
一次 移动 是指选择任一行或列，并转换该行或列中的每一个值：将所有 0 都更改为 1，将所有 1 都更改为 0。
在做出任意次数的移动后，将该矩阵的每一行都按照二进制数来解释，矩阵的 得分 就是这些数字的总和。
\n\n在执行任意次 移动 后（含 0 次），返回可能的最高分数。
\n\n\n\n
示例 1：
\n\n\n输入：grid = [[0,0,1,1],[1,0,1,0],[1,1,0,0]]\n输出：39\n解释：0b1111 + 0b1001 + 0b1111 = 15 + 9 + 15 = 39\n\n\n
示例 2：
\n\n\n输入：grid = [[0]]\n输出：1\n\n\n
\n\n
提示：
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