Given a 0-indexed string word and a character ch, reverse the segment of word that starts at index 0 and ends at the index of the first occurrence of ch (inclusive). If the character ch does not exist in word, do nothing.
word = "abcdefd" and ch = "d", then you should reverse the segment that starts at 0 and ends at 3 (inclusive). The resulting string will be "dcbaefd".Return the resulting string.
\n\n\n
Example 1:
\n\n\nInput: word = "abcdefd", ch = "d"\nOutput: "dcbaefd"\nExplanation: The first occurrence of "d" is at index 3. \nReverse the part of word from 0 to 3 (inclusive), the resulting string is "dcbaefd".\n\n\n
Example 2:
\n\n\nInput: word = "xyxzxe", ch = "z"\nOutput: "zxyxxe"\nExplanation: The first and only occurrence of "z" is at index 3.\nReverse the part of word from 0 to 3 (inclusive), the resulting string is "zxyxxe".\n\n\n
Example 3:
\n\n\nInput: word = "abcd", ch = "z"\nOutput: "abcd"\nExplanation: "z" does not exist in word.\nYou should not do any reverse operation, the resulting string is "abcd".\n\n\n
\n
Constraints:
\n\n1 <= word.length <= 250word consists of lowercase English letters.ch is a lowercase English letter.给你一个下标从 0 开始的字符串 word 和一个字符 ch 。找出 ch 第一次出现的下标 i ，反转 word 中从下标 0 开始、直到下标 i 结束（含下标 i ）的那段字符。如果 word 中不存在字符 ch ，则无需进行任何操作。
word = \"abcdefd\" 且 ch = \"d\" ，那么你应该 反转 从下标 0 开始、直到下标 3 结束（含下标 3 ）。结果字符串将会是 \"dcbaefd\" 。返回 结果字符串 。
\n\n\n\n
示例 1：
\n\n输入：word = \"abcdefd\", ch = \"d\"\n输出：\"dcbaefd\"\n解释：\"d\" 第一次出现在下标 3 。 \n反转从下标 0 到下标 3（含下标 3）的这段字符，结果字符串是 \"dcbaefd\" 。\n\n\n
示例 2：
\n\n输入：word = \"xyxzxe\", ch = \"z\"\n输出：\"zxyxxe\"\n解释：\"z\" 第一次也是唯一一次出现是在下标 3 。\n反转从下标 0 到下标 3（含下标 3）的这段字符，结果字符串是 \"zxyxxe\" 。\n\n\n
示例 3：
\n\n输入：word = \"abcd\", ch = \"z\"\n输出：\"abcd\"\n解释：\"z\" 不存在于 word 中。\n无需执行反转操作，结果字符串是 \"abcd\" 。\n\n\n
\n\n
提示：
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"exampleTestcases": "\"abcdefd\"\n\"d\"\n\"xyxzxe\"\n\"z\"\n\"abcd\"\n\"z\"",
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