You are given two strings s and p where p is a subsequence of s. You are also given a distinct 0-indexed integer array removable containing a subset of indices of s (s is also 0-indexed).
You want to choose an integer k (0 <= k <= removable.length) such that, after removing k characters from s using the first k indices in removable, p is still a subsequence of s. More formally, you will mark the character at s[removable[i]] for each 0 <= i < k, then remove all marked characters and check if p is still a subsequence.
Return the maximum k you can choose such that p is still a subsequence of s after the removals.
A subsequence of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters.
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Example 1:
\n\n\nInput: s = "abcacb", p = "ab", removable = [3,1,0]\nOutput: 2\nExplanation: After removing the characters at indices 3 and 1, "a\n\nbcacb" becomes "accb".\n"ab" is a subsequence of "accb".\nIf we remove the characters at indices 3, 1, and 0, "abcacb" becomes "ccb", and "ab" is no longer a subsequence.\nHence, the maximum k is 2.\n
Example 2:
\n\n\nInput: s = "abcbddddd", p = "abcd", removable = [3,2,1,4,5,6]\nOutput: 1\nExplanation: After removing the character at index 3, "abc\n\nbddddd" becomes "abcddddd".\n"abcd" is a subsequence of "abcddddd".\n
Example 3:
\n\n\nInput: s = "abcab", p = "abc", removable = [0,1,2,3,4]\nOutput: 0\nExplanation: If you remove the first index in the array removable, "abc" is no longer a subsequence.\n\n\n
\n
Constraints:
\n\n1 <= p.length <= s.length <= 1050 <= removable.length < s.length0 <= removable[i] < s.lengthp is a subsequence of s.s and p both consist of lowercase English letters.removable are distinct.给你两个字符串 s 和 p ，其中 p 是 s 的一个 子序列 。同时，给你一个元素 互不相同 且下标 从 0 开始 计数的整数数组 removable ，该数组是 s 中下标的一个子集（s 的下标也 从 0 开始 计数）。
请你找出一个整数 k（0 <= k <= removable.length），选出 removable 中的 前 k 个下标，然后从 s 中移除这些下标对应的 k 个字符。整数 k 需满足：在执行完上述步骤后， p 仍然是 s 的一个 子序列 。更正式的解释是，对于每个 0 <= i < k ，先标记出位于 s[removable[i]] 的字符，接着移除所有标记过的字符，然后检查 p 是否仍然是 s 的一个子序列。
返回你可以找出的 最大 k ，满足在移除字符后 p 仍然是 s 的一个子序列。
字符串的一个 子序列 是一个由原字符串生成的新字符串，生成过程中可能会移除原字符串中的一些字符（也可能不移除）但不改变剩余字符之间的相对顺序。
\n\n\n\n
示例 1：
\n\n\n输入：s = \"abcacb\", p = \"ab\", removable = [3,1,0]\n输出：2\n解释：在移除下标 3 和 1 对应的字符后，\"abcacb\" 变成 \"accb\" 。\n\"ab\" 是 \"accb\" 的一个子序列。\n如果移除下标 3、1 和 0 对应的字符后，\"abcacb\" 变成 \"ccb\" ，那么 \"ab\" 就不再是 s 的一个子序列。\n因此，最大的 k 是 2 。\n\n\n
示例 2：
\n\n\n输入：s = \"abcbddddd\", p = \"abcd\", removable = [3,2,1,4,5,6]\n输出：1\n解释：在移除下标 3 对应的字符后，\"abcbddddd\" 变成 \"abcddddd\" 。\n\"abcd\" 是 \"abcddddd\" 的一个子序列。\n\n\n
示例 3：
\n\n\n输入：s = \"abcab\", p = \"abc\", removable = [0,1,2,3,4]\n输出：0\n解释：如果移除数组 removable 的第一个下标，\"abc\" 就不再是 s 的一个子序列。\n\n\n
\n\n
提示：
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