You are given an integer array nums. The absolute sum of a subarray [numsl, numsl+1, ..., numsr-1, numsr] is abs(numsl + numsl+1 + ... + numsr-1 + numsr).
Return the maximum absolute sum of any (possibly empty) subarray of nums.
Note that abs(x) is defined as follows:
x is a negative integer, then abs(x) = -x.x is a non-negative integer, then abs(x) = x.\n
Example 1:
\n\n\nInput: nums = [1,-3,2,3,-4]\nOutput: 5\nExplanation: The subarray [2,3] has absolute sum = abs(2+3) = abs(5) = 5.\n\n\n
Example 2:
\n\n\nInput: nums = [2,-5,1,-4,3,-2]\nOutput: 8\nExplanation: The subarray [-5,1,-4] has absolute sum = abs(-5+1-4) = abs(-8) = 8.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 105-104 <= nums[i] <= 104给你一个整数数组 nums 。一个子数组 [numsl, numsl+1, ..., numsr-1, numsr] 的 和的绝对值 为 abs(numsl + numsl+1 + ... + numsr-1 + numsr) 。
请你找出 nums 中 和的绝对值 最大的任意子数组（可能为空），并返回该 最大值 。
abs(x) 定义如下：
x 是负整数，那么 abs(x) = -x 。x 是非负整数，那么 abs(x) = x 。\n\n
示例 1：
\n\n\n输入：nums = [1,-3,2,3,-4]\n输出：5\n解释：子数组 [2,3] 和的绝对值最大，为 abs(2+3) = abs(5) = 5 。\n\n\n
示例 2：
\n\n\n输入：nums = [2,-5,1,-4,3,-2]\n输出：8\n解释：子数组 [-5,1,-4] 和的绝对值最大，为 abs(-5+1-4) = abs(-8) = 8 。\n\n\n
\n\n
提示：
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