You are given two integer arrays nums and divisors.
The divisibility score of divisors[i] is the number of indices j such that nums[j] is divisible by divisors[i].
Return the integer divisors[i] with the maximum divisibility score. If multiple integers have the maximum score, return the smallest one.
\n
Example 1:
\n\nInput: nums = [2,9,15,50], divisors = [5,3,7,2]
\n\nOutput: 2
\n\nExplanation:
\n\nThe divisibility score of divisors[0] is 2 since nums[2] and nums[3] are divisible by 5.
The divisibility score of divisors[1] is 2 since nums[1] and nums[2] are divisible by 3.
The divisibility score of divisors[2] is 0 since none of the numbers in nums is divisible by 7.
The divisibility score of divisors[3] is 2 since nums[0] and nums[3] are divisible by 2.
As divisors[0], divisors[1], and divisors[3] have the same divisibility score, we return the smaller one which is divisors[3].
Example 2:
\n\nInput: nums = [4,7,9,3,9], divisors = [5,2,3]
\n\nOutput: 3
\n\nExplanation:
\n\nThe divisibility score of divisors[0] is 0 since none of numbers in nums is divisible by 5.
The divisibility score of divisors[1] is 1 since only nums[0] is divisible by 2.
The divisibility score of divisors[2] is 3 since nums[2], nums[3] and nums[4] are divisible by 3.
Example 3:
\n\nInput: nums = [20,14,21,10], divisors = [10,16,20]
\n\nOutput: 10
\n\nExplanation:
\n\nThe divisibility score of divisors[0] is 2 since nums[0] and nums[3] are divisible by 10.
The divisibility score of divisors[1] is 0 since none of the numbers in nums is divisible by 16.
The divisibility score of divisors[2] is 1 since nums[0] is divisible by 20.
\n
Constraints:
\n\n1 <= nums.length, divisors.length <= 10001 <= nums[i], divisors[i] <= 109给你两个整数数组 nums 和 divisors 。
divisors[i] 的 可整除性得分 等于满足 nums[j] 能被 divisors[i] 整除的下标 j 的数量。
返回 可整除性得分 最大的整数 divisors[i] 。如果有多个整数具有最大得分，则返回数值最小的一个。
\n\n
示例 1：
\n\n输入：nums = [2,9,15,50], divisors = [5,3,7,2]
\n\n输出：2
\n\n解释：
\n\ndivisors[0] 的可整除性分数为 2 因为 nums[2] 和 nums[3] 能被 5 整除。
divisors[1] 的可整除性分数为 2 因为 nums[1] 和 nums[2] 能被 3 整除。
divisors[2] 的可整除性分数为 0 因为 nums 中没有数字能被 7 整除。
divisors[3] 的可整除性分数为 2 因为 nums[0] 和 nums[3] 能够被 2 整除。
因为 divisors[0] 、divisor[1] 和 divisors[3] 有相同的可整除性分数，我们返回更小的那个 divisors[3]。
示例 2：
\n\n输入：nums = [4,7,9,3,9], divisors = [5,2,3]
\n\n输出：3
\n\n解释：
\n\ndivisors[0] 的可整除性分数为 0 因为 nums 中没有数字能被 5 整除。
divisors[1] 的可整除性分数为 1 因为只有 nums[0] 能被 2 整除。
divisors[2] 的可整除性分数为 3 因为 nums[2] ，nums[3] 和 nums[4] 能被 3 整除。
示例 3：
\n\n输入：nums = [20,14,21,10], divisors = [10,16,20]
\n\n输出：10
\n\n解释：
\n\ndivisors[0] 的可整除性分数为 2 因为 nums[0] 和 nums[3] 能被 10 整除。
divisors[1] 的可整除性分数为 0 因为 nums 中没有数字能被 16 整除。
divisors[2] 的可整除性分数为 1 因为 nums[0] 能被 20 整除。
因为 divisors[0] 的可整除性分数最大，我们返回 divisors[0]。
\n\n
提示：
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