You are given two integer arrays nums1 and nums2.
From nums1 two elements have been removed, and all other elements have been increased (or decreased in the case of negative) by an integer, represented by the variable x.
As a result, nums1 becomes equal to nums2. Two arrays are considered equal when they contain the same integers with the same frequencies.
Return the minimum possible integer x that achieves this equivalence.
\n
Example 1:
\n\nInput: nums1 = [4,20,16,12,8], nums2 = [14,18,10]
\n\nOutput: -2
\n\nExplanation:
\n\nAfter removing elements at indices [0,4] and adding -2, nums1 becomes [18,14,10].
Example 2:
\n\nInput: nums1 = [3,5,5,3], nums2 = [7,7]
\n\nOutput: 2
\n\nExplanation:
\n\nAfter removing elements at indices [0,3] and adding 2, nums1 becomes [7,7].
\n
Constraints:
\n\n3 <= nums1.length <= 200nums2.length == nums1.length - 20 <= nums1[i], nums2[i] <= 1000x such that nums1 can become equal to nums2 by removing two elements and adding x to each element of nums1.给你两个整数数组 nums1 和 nums2。
从 nums1 中移除两个元素，并且所有其他元素都与变量 x 所表示的整数相加。如果 x 为负数，则表现为元素值的减少。
执行上述操作后，nums1 和 nums2 相等 。当两个数组中包含相同的整数，并且这些整数出现的频次相同时，两个数组 相等 。
返回能够实现数组相等的 最小 整数 x 。
\n\n
示例 1:
\n\n输入：nums1 = [4,20,16,12,8], nums2 = [14,18,10]
\n\n输出：-2
\n\n解释：
\n\n移除 nums1 中下标为 [0,4] 的两个元素，并且每个元素与 -2 相加后，nums1 变为 [18,14,10] ，与 nums2 相等。
示例 2:
\n\n输入：nums1 = [3,5,5,3], nums2 = [7,7]
\n\n输出：2
\n\n解释：
\n\n移除 nums1 中下标为 [0,3] 的两个元素，并且每个元素与 2 相加后，nums1 变为 [7,7] ，与 nums2 相等。
\n\n
提示：
\n\n3 <= nums1.length <= 200nums2.length == nums1.length - 20 <= nums1[i], nums2[i] <= 1000x，nums1 中的每个元素都与 x 相加后，再移除两个元素，nums1 可以与 nums2 相等。nums1.",
"x should be equal to min(nums2) - min(nums1), check it naively."
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