{ "data": { "question": { "questionId": "105", "questionFrontendId": "105", "categoryTitle": "Algorithms", "boundTopicId": 1168, "title": "Construct Binary Tree from Preorder and Inorder Traversal", "titleSlug": "construct-binary-tree-from-preorder-and-inorder-traversal", "content": "
Given two integer arrays preorder
and inorder
where preorder
is the preorder traversal of a binary tree and inorder
is the inorder traversal of the same tree, construct and return the binary tree.
\n
Example 1:
\n\nInput: preorder = [3,9,20,15,7], inorder = [9,3,15,20,7]\nOutput: [3,9,20,null,null,15,7]\n\n\n
Example 2:
\n\n\nInput: preorder = [-1], inorder = [-1]\nOutput: [-1]\n\n\n
\n
Constraints:
\n\n1 <= preorder.length <= 3000
inorder.length == preorder.length
-3000 <= preorder[i], inorder[i] <= 3000
preorder
and inorder
consist of unique values.inorder
also appears in preorder
.preorder
is guaranteed to be the preorder traversal of the tree.inorder
is guaranteed to be the inorder traversal of the tree.给定两个整数数组 preorder
和 inorder
,其中 preorder
是二叉树的先序遍历, inorder
是同一棵树的中序遍历,请构造二叉树并返回其根节点。
\n\n
示例 1:
\n\n输入: preorder = [3,9,20,15,7], inorder = [9,3,15,20,7]\n输出: [3,9,20,null,null,15,7]\n\n\n
示例 2:
\n\n\n输入: preorder = [-1], inorder = [-1]\n输出: [-1]\n\n\n
\n\n
提示:
\n\n1 <= preorder.length <= 3000
inorder.length == preorder.length
-3000 <= preorder[i], inorder[i] <= 3000
preorder
和 inorder
均 无重复 元素inorder
均出现在 preorder
preorder
保证 为二叉树的前序遍历序列inorder
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"exampleTestcases": "[3,9,20,15,7]\n[9,3,15,20,7]\n[-1]\n[-1]",
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