You are given two integers n and t. Return the smallest number greater than or equal to n such that the product of its digits is divisible by t.
\n
Example 1:
\n\nInput: n = 10, t = 2
\n\nOutput: 10
\n\nExplanation:
\n\nThe digit product of 10 is 0, which is divisible by 2, making it the smallest number greater than or equal to 10 that satisfies the condition.
\nExample 2:
\n\nInput: n = 15, t = 3
\n\nOutput: 16
\n\nExplanation:
\n\nThe digit product of 16 is 6, which is divisible by 3, making it the smallest number greater than or equal to 15 that satisfies the condition.
\n\n
Constraints:
\n\n1 <= n <= 1001 <= t <= 10给你两个整数 n 和 t 。请你返回大于等于 n 的 最小 整数，且该整数的 各数位之积 能被 t 整除。
\n\n
示例 1：
\n\n输入：n = 10, t = 2
\n\n输出：10
\n\n解释：
\n\n10 的数位乘积为 0 ，可以被 2 整除，所以它是大于等于 10 且满足题目要求的最小整数。
\n示例 2：
\n\n输入：n = 15, t = 3
\n\n输出：16
\n\n解释：
\n\n16 的数位乘积为 6 ，可以被 3 整除，所以它是大于等于 15 且满足题目要求的最小整数。
\n\n\n
提示：
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