You are given a 2D integer array intervals, where intervals[i] = [li, ri, weighti]. Interval i starts at position li and ends at ri, and has a weight of weighti. You can choose up to 4 non-overlapping intervals. The score of the chosen intervals is defined as the total sum of their weights.
Return the lexicographically smallest array of at most 4 indices from intervals with maximum score, representing your choice of non-overlapping intervals.
Two intervals are said to be non-overlapping if they do not share any points. In particular, intervals sharing a left or right boundary are considered overlapping.
\n\n\n
Example 1:
\n\nInput: intervals = [[1,3,2],[4,5,2],[1,5,5],[6,9,3],[6,7,1],[8,9,1]]
\n\nOutput: [2,3]
\n\nExplanation:
\n\nYou can choose the intervals with indices 2, and 3 with respective weights of 5, and 3.
\nExample 2:
\n\nInput: intervals = [[5,8,1],[6,7,7],[4,7,3],[9,10,6],[7,8,2],[11,14,3],[3,5,5]]
\n\nOutput: [1,3,5,6]
\n\nExplanation:
\n\nYou can choose the intervals with indices 1, 3, 5, and 6 with respective weights of 7, 6, 3, and 5.
\n\n
Constraints:
\n\n1 <= intevals.length <= 5 * 104intervals[i].length == 3intervals[i] = [li, ri, weighti]1 <= li <= ri <= 1091 <= weighti <= 109给你一个二维整数数组 intervals，其中 intervals[i] = [li, ri, weighti]。区间 i 的起点为 li，终点为 ri，权重为 weighti。你最多可以选择 4 个互不重叠 的区间。所选择区间的 得分 定义为这些区间权重的总和。
返回一个至多包含 4 个下标且 字典序最小 的数组，表示从 intervals 中选中的互不重叠且得分最大的区间。
如果两个区间没有任何重叠点，则称二者 互不重叠 。特别地，如果两个区间共享左边界或右边界，也认为二者重叠。
\n\n\n\n
示例 1：
\n\n输入： intervals = [[1,3,2],[4,5,2],[1,5,5],[6,9,3],[6,7,1],[8,9,1]]
\n\n输出： [2,3]
\n\n解释：
\n\n可以选择下标为 2 和 3 的区间，其权重分别为 5 和 3。
\n示例 2：
\n\n输入： intervals = [[5,8,1],[6,7,7],[4,7,3],[9,10,6],[7,8,2],[11,14,3],[3,5,5]]
\n\n输出： [1,3,5,6]
\n\n解释：
\n\n可以选择下标为 1、3、5 和 6 的区间，其权重分别为 7、6、3 和 5。
\n\n\n
提示：
\n\n1 <= intervals.length <= 5 * 104intervals[i].length == 3intervals[i] = [li, ri, weighti]1 <= li <= ri <= 1091 <= weighti <= 109intervals by right boundary.",
"Let dp[r][i] denote the maximum score having picked r intervals from the prefix of intervals ending at index i.",
"dp[r][i] = max(dp[r][i - 1], intervals[i][2] + dp[r][j]) where j is the largest index such that intervals[j][1] < intervals[i][0].",
"Since intervals is sorted by right boundary, we can find index j using binary search."
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