You are given an integer array nums.
You can do the following operation on the array at most once:
\n\nx such that nums remains non-empty on removing all occurrences of x.x from the array.Return the maximum subarray sum across all possible resulting arrays.
\n\n\n
Example 1:
\n\nInput: nums = [-3,2,-2,-1,3,-2,3]
\n\nOutput: 7
\n\nExplanation:
\n\nWe can have the following arrays after at most one operation:
\n\nnums = [-3, 2, -2, -1, 3, -2, 3]. The maximum subarray sum is 3 + (-2) + 3 = 4.x = -3 results in nums = [2, -2, -1, 3, -2, 3]. The maximum subarray sum is 3 + (-2) + 3 = 4.x = -2 results in nums = [-3, 2, -1, 3, 3]. The maximum subarray sum is 2 + (-1) + 3 + 3 = 7.x = -1 results in nums = [-3, 2, -2, 3, -2, 3]. The maximum subarray sum is 3 + (-2) + 3 = 4.x = 3 results in nums = [-3, 2, -2, -1, -2]. The maximum subarray sum is 2.The output is max(4, 4, 7, 4, 2) = 7.
Example 2:
\n\nInput: nums = [1,2,3,4]
\n\nOutput: 10
\n\nExplanation:
\n\nIt is optimal to not perform any operations.
\n\n
Constraints:
\n\n1 <= nums.length <= 105-106 <= nums[i] <= 106给你一个整数数组 nums 。
你可以对数组执行以下操作 至多 一次：
\n\nnums 中存在的 任意 整数 X ，确保删除所有值为 X 的元素后剩下数组 非空 。X 的元素都删除。请你返回 所有 可能得到的数组中 最大 子数组 和为多少。
\n\n\n\n
示例 1：
\n\n输入：nums = [-3,2,-2,-1,3,-2,3]
\n\n输出：7
\n\n解释：
\n\n我们执行至多一次操作后可以得到以下数组：
\n\nnums = [-3, 2, -2, -1, 3, -2, 3] 。最大子数组和为 3 + (-2) + 3 = 4 。X = -3 后得到 nums = [2, -2, -1, 3, -2, 3] 。最大子数组和为 3 + (-2) + 3 = 4 。X = -2 后得到 nums = [-3, 2, -1, 3, 3] 。最大子数组和为 2 + (-1) + 3 + 3 = 7 。X = -1 后得到 nums = [-3, 2, -2, 3, -2, 3] 。最大子数组和为 3 + (-2) + 3 = 4 。X = 3 后得到 nums = [-3, 2, -2, -1, -2] 。最大子数组和为 2 。输出为 max(4, 4, 7, 4, 2) = 7 。
示例 2：
\n\n输入：nums = [1,2,3,4]
\n\n输出：10
\n\n解释：
\n\n最优操作是不删除任何元素。
\n\n\n
提示：
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