{ "data": { "question": { "questionId": "3588", "questionFrontendId": "3320", "categoryTitle": "Algorithms", "boundTopicId": 2945079, "title": "Count The Number of Winning Sequences", "titleSlug": "count-the-number-of-winning-sequences", "content": "
Alice and Bob are playing a fantasy battle game consisting of n
rounds where they summon one of three magical creatures each round: a Fire Dragon, a Water Serpent, or an Earth Golem. In each round, players simultaneously summon their creature and are awarded points as follows:
You are given a string s
consisting of n
characters 'F'
, 'W'
, and 'E'
, representing the sequence of creatures Alice will summon in each round:
s[i] == 'F'
, Alice summons a Fire Dragon.s[i] == 'W'
, Alice summons a Water Serpent.s[i] == 'E'
, Alice summons an Earth Golem.Bob’s sequence of moves is unknown, but it is guaranteed that Bob will never summon the same creature in two consecutive rounds. Bob beats Alice if the total number of points awarded to Bob after n
rounds is strictly greater than the points awarded to Alice.
Return the number of distinct sequences Bob can use to beat Alice.
\n\nSince the answer may be very large, return it modulo 109 + 7
.
\n
Example 1:
\n\nInput: s = "FFF"
\n\nOutput: 3
\n\nExplanation:
\n\nBob can beat Alice by making one of the following sequences of moves: "WFW"
, "FWF"
, or "WEW"
. Note that other winning sequences like "WWE"
or "EWW"
are invalid since Bob cannot make the same move twice in a row.
Example 2:
\n\nInput: s = "FWEFW"
\n\nOutput: 18
\n\nExplanation:
\n\n"FWFWF"
, "FWFWE"
, "FWEFE"
, "FWEWE"
, "FEFWF"
, "FEFWE"
, "FEFEW"
, "FEWFE"
, "WFEFE"
, "WFEWE"
, "WEFWF"
, "WEFWE"
, "WEFEF"
, "WEFEW"
, "WEWFW"
, "WEWFE"
, "EWFWE"
, or "EWEWE"
.
\n
Constraints:
\n\n1 <= s.length <= 1000
s[i]
is one of 'F'
, 'W'
, or 'E'
.Alice 和 Bob 正在玩一个幻想战斗游戏,游戏共有 n
回合,每回合双方各自都会召唤一个魔法生物:火龙(F
)、水蛇(W
)或地精(E
)。每回合中,双方 同时 召唤魔法生物,并根据以下规则得分:
给你一个字符串 s
,包含 n
个字符 'F'
、'W'
和 'E'
,代表 Alice 每回合召唤的生物序列:
s[i] == 'F'
,Alice 召唤火龙。s[i] == 'W'
,Alice 召唤水蛇。s[i] == 'E'
,Alice 召唤地精。Bob 的出招序列未知,但保证 Bob 不会在连续两个回合中召唤相同的生物。如果在 n
轮后 Bob 获得的总分 严格大于 Alice 的总分,则 Bob 战胜 Alice。
返回 Bob 可以用来战胜 Alice 的不同出招序列的数量。
\n\n由于答案可能非常大,请返回答案对 109 + 7
取余 后的结果。
\n\n
示例 1:
\n\n输入: s = \"FFF\"
\n\n输出: 3
\n\n解释:
\n\nBob 可以通过以下 3 种出招序列战胜 Alice:\"WFW\"
、\"FWF\"
或 \"WEW\"
。注意,其他如 \"WWE\"
或 \"EWW\"
的出招序列是无效的,因为 Bob 不能在连续两个回合中使用相同的生物。
示例 2:
\n\n输入: s = \"FWEFW\"
\n\n输出: 18
\n\n解释:
\n\nBob 可以通过以下出招序列战胜 Alice:\"FWFWF\"
、\"FWFWE\"
、\"FWEFE\"
、\"FWEWE\"
、\"FEFWF\"
、\"FEFWE\"
、\"FEFEW\"
、\"FEWFE\"
、\"WFEFE\"
、\"WFEWE\"
、\"WEFWF\"
、\"WEFWE\"
、\"WEFEF\"
、\"WEFEW\"
、\"WEWFW\"
、\"WEWFE\"
、\"EWFWE\"
或 \"EWEWE\"
。
\n\n
提示:
\n\n1 <= s.length <= 1000
s[i]
是 'F'
、'W'
或 'E'
中的一个。0 < i < n - 1
, -n < j < n
, and k
in {’F’, ‘W’, ‘E’}
, let dp[i][j][k]
be the number of sequences consisting of the first i
moves such that the difference between bob’s points and alice’s point is equal to j
and the ith
move that Bob played is k
.",
"The answer is the sum of dp[n - 1][j][k]
over all j > 0
and over all k
."
],
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