You are given two positive integer arrays spells and potions, of length n and m respectively, where spells[i] represents the strength of the ith spell and potions[j] represents the strength of the jth potion.
You are also given an integer success. A spell and potion pair is considered successful if the product of their strengths is at least success.
Return an integer array pairs of length n where pairs[i] is the number of potions that will form a successful pair with the ith spell.
\n
Example 1:
\n\n\nInput: spells = [5,1,3], potions = [1,2,3,4,5], success = 7\nOutput: [4,0,3]\nExplanation:\n- 0th spell: 5 * [1,2,3,4,5] = [5,10,15,20,25]. 4 pairs are successful.\n- 1st spell: 1 * [1,2,3,4,5] = [1,2,3,4,5]. 0 pairs are successful.\n- 2nd spell: 3 * [1,2,3,4,5] = [3,6,9,12,15]. 3 pairs are successful.\nThus, [4,0,3] is returned.\n\n\n
Example 2:
\n\n\nInput: spells = [3,1,2], potions = [8,5,8], success = 16\nOutput: [2,0,2]\nExplanation:\n- 0th spell: 3 * [8,5,8] = [24,15,24]. 2 pairs are successful.\n- 1st spell: 1 * [8,5,8] = [8,5,8]. 0 pairs are successful. \n- 2nd spell: 2 * [8,5,8] = [16,10,16]. 2 pairs are successful. \nThus, [2,0,2] is returned.\n\n\n
\n
Constraints:
\n\nn == spells.lengthm == potions.length1 <= n, m <= 1051 <= spells[i], potions[i] <= 1051 <= success <= 1010给你两个正整数数组 spells 和 potions ，长度分别为 n 和 m ，其中 spells[i] 表示第 i 个咒语的能量强度，potions[j] 表示第 j 瓶药水的能量强度。
同时给你一个整数 success 。一个咒语和药水的能量强度 相乘 如果 大于等于 success ，那么它们视为一对 成功 的组合。
请你返回一个长度为 n 的整数数组 pairs，其中 pairs[i] 是能跟第 i 个咒语成功组合的 药水 数目。
\n\n
示例 1：
\n\n输入：spells = [5,1,3], potions = [1,2,3,4,5], success = 7\n输出：[4,0,3]\n解释：\n- 第 0 个咒语：5 * [1,2,3,4,5] = [5,10,15,20,25] 。总共 4 个成功组合。\n- 第 1 个咒语：1 * [1,2,3,4,5] = [1,2,3,4,5] 。总共 0 个成功组合。\n- 第 2 个咒语：3 * [1,2,3,4,5] = [3,6,9,12,15] 。总共 3 个成功组合。\n所以返回 [4,0,3] 。\n\n\n
示例 2：
\n\n输入：spells = [3,1,2], potions = [8,5,8], success = 16\n输出：[2,0,2]\n解释：\n- 第 0 个咒语：3 * [8,5,8] = [24,15,24] 。总共 2 个成功组合。\n- 第 1 个咒语：1 * [8,5,8] = [8,5,8] 。总共 0 个成功组合。\n- 第 2 个咒语：2 * [8,5,8] = [16,10,16] 。总共 2 个成功组合。\n所以返回 [2,0,2] 。\n\n\n
\n\n
提示：
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