{ "data": { "question": { "questionId": "2176", "questionFrontendId": "2050", "boundTopicId": null, "title": "Parallel Courses III", "titleSlug": "parallel-courses-iii", "content": "
You are given an integer n
, which indicates that there are n
courses labeled from 1
to n
. You are also given a 2D integer array relations
where relations[j] = [prevCoursej, nextCoursej]
denotes that course prevCoursej
has to be completed before course nextCoursej
(prerequisite relationship). Furthermore, you are given a 0-indexed integer array time
where time[i]
denotes how many months it takes to complete the (i+1)th
course.
You must find the minimum number of months needed to complete all the courses following these rules:
\n\nReturn the minimum number of months needed to complete all the courses.
\n\nNote: The test cases are generated such that it is possible to complete every course (i.e., the graph is a directed acyclic graph).
\n\n\n
Example 1:
\n\n\n\nInput: n = 3, relations = [[1,3],[2,3]], time = [3,2,5]\nOutput: 8\nExplanation: The figure above represents the given graph and the time required to complete each course. \nWe start course 1 and course 2 simultaneously at month 0.\nCourse 1 takes 3 months and course 2 takes 2 months to complete respectively.\nThus, the earliest time we can start course 3 is at month 3, and the total time required is 3 + 5 = 8 months.\n\n\n
Example 2:
\n\n\n\nInput: n = 5, relations = [[1,5],[2,5],[3,5],[3,4],[4,5]], time = [1,2,3,4,5]\nOutput: 12\nExplanation: The figure above represents the given graph and the time required to complete each course.\nYou can start courses 1, 2, and 3 at month 0.\nYou can complete them after 1, 2, and 3 months respectively.\nCourse 4 can be taken only after course 3 is completed, i.e., after 3 months. It is completed after 3 + 4 = 7 months.\nCourse 5 can be taken only after courses 1, 2, 3, and 4 have been completed, i.e., after max(1,2,3,7) = 7 months.\nThus, the minimum time needed to complete all the courses is 7 + 5 = 12 months.\n\n\n
\n
Constraints:
\n\n1 <= n <= 5 * 104
0 <= relations.length <= min(n * (n - 1) / 2, 5 * 104)
relations[j].length == 2
1 <= prevCoursej, nextCoursej <= n
prevCoursej != nextCoursej
[prevCoursej, nextCoursej]
are unique.time.length == n
1 <= time[i] <= 104
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