{ "data": { "question": { "questionId": "802", "questionFrontendId": "786", "boundTopicId": null, "title": "K-th Smallest Prime Fraction", "titleSlug": "k-th-smallest-prime-fraction", "content": "
You are given a sorted integer array arr
containing 1
and prime numbers, where all the integers of arr
are unique. You are also given an integer k
.
For every i
and j
where 0 <= i < j < arr.length
, we consider the fraction arr[i] / arr[j]
.
Return the kth
smallest fraction considered. Return your answer as an array of integers of size 2
, where answer[0] == arr[i]
and answer[1] == arr[j]
.
\n
Example 1:
\n\n\nInput: arr = [1,2,3,5], k = 3\nOutput: [2,5]\nExplanation: The fractions to be considered in sorted order are:\n1/5, 1/3, 2/5, 1/2, 3/5, and 2/3.\nThe third fraction is 2/5.\n\n\n
Example 2:
\n\n\nInput: arr = [1,7], k = 1\nOutput: [1,7]\n\n\n
\n
Constraints:
\n\n2 <= arr.length <= 1000
1 <= arr[i] <= 3 * 104
arr[0] == 1
arr[i]
is a prime number for i > 0
.arr
are unique and sorted in strictly increasing order.1 <= k <= arr.length * (arr.length - 1) / 2
Compiled with clang 11
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Most standard library headers are already included automatically for your convenience.
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