{ "data": { "question": { "questionId": "2324", "questionFrontendId": "2221", "boundTopicId": null, "title": "Find Triangular Sum of an Array", "titleSlug": "find-triangular-sum-of-an-array", "content": "

You are given a 0-indexed integer array nums, where nums[i] is a digit between 0 and 9 (inclusive).

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The triangular sum of nums is the value of the only element present in nums after the following process terminates:

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    \n\t
  1. Let nums comprise of n elements. If n == 1, end the process. Otherwise, create a new 0-indexed integer array newNums of length n - 1.
  2. \n\t
  3. For each index i, where 0 <= i < n - 1, assign the value of newNums[i] as (nums[i] + nums[i+1]) % 10, where % denotes modulo operator.
  4. \n\t
  5. Replace the array nums with newNums.
  6. \n\t
  7. Repeat the entire process starting from step 1.
  8. \n
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Return the triangular sum of nums.

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Example 1:

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\nInput: nums = [1,2,3,4,5]\nOutput: 8\nExplanation:\nThe above diagram depicts the process from which we obtain the triangular sum of the array.
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Example 2:

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\nInput: nums = [5]\nOutput: 5\nExplanation:\nSince there is only one element in nums, the triangular sum is the value of that element itself.
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Constraints:

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