{ "data": { "question": { "questionId": "2175", "questionFrontendId": "2049", "boundTopicId": null, "title": "Count Nodes With the Highest Score", "titleSlug": "count-nodes-with-the-highest-score", "content": "
There is a binary tree rooted at 0
consisting of n
nodes. The nodes are labeled from 0
to n - 1
. You are given a 0-indexed integer array parents
representing the tree, where parents[i]
is the parent of node i
. Since node 0
is the root, parents[0] == -1
.
Each node has a score. To find the score of a node, consider if the node and the edges connected to it were removed. The tree would become one or more non-empty subtrees. The size of a subtree is the number of the nodes in it. The score of the node is the product of the sizes of all those subtrees.
\n\nReturn the number of nodes that have the highest score.
\n\n\n
Example 1:
\n\n\nInput: parents = [-1,2,0,2,0]\nOutput: 3\nExplanation:\n- The score of node 0 is: 3 * 1 = 3\n- The score of node 1 is: 4 = 4\n- The score of node 2 is: 1 * 1 * 2 = 2\n- The score of node 3 is: 4 = 4\n- The score of node 4 is: 4 = 4\nThe highest score is 4, and three nodes (node 1, node 3, and node 4) have the highest score.\n\n\n
Example 2:
\n\n\nInput: parents = [-1,2,0]\nOutput: 2\nExplanation:\n- The score of node 0 is: 2 = 2\n- The score of node 1 is: 2 = 2\n- The score of node 2 is: 1 * 1 = 1\nThe highest score is 2, and two nodes (node 0 and node 1) have the highest score.\n\n\n
\n
Constraints:
\n\nn == parents.length
2 <= n <= 105
parents[0] == -1
0 <= parents[i] <= n - 1
for i != 0
parents
represents a valid binary tree.Compiled with clang 11
using the latest C++ 17 standard.
Your code is compiled with level two optimization (-O2
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Most standard library headers are already included automatically for your convenience.
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