You are given a 0-indexed integer array nums and an integer pivot. Rearrange nums such that the following conditions are satisfied:
pivot appears before every element greater than pivot.pivot appears in between the elements less than and greater than pivot.pivot and the elements greater than pivot is maintained.\n\tpi, pj where pi is the new position of the ith element and pj is the new position of the jth element. For elements less than pivot, if i < j and nums[i] < pivot and nums[j] < pivot, then pi < pj. Similarly for elements greater than pivot, if i < j and nums[i] > pivot and nums[j] > pivot, then pi < pj.Return nums after the rearrangement.
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Example 1:
\n\n\nInput: nums = [9,12,5,10,14,3,10], pivot = 10\nOutput: [9,5,3,10,10,12,14]\nExplanation: \nThe elements 9, 5, and 3 are less than the pivot so they are on the left side of the array.\nThe elements 12 and 14 are greater than the pivot so they are on the right side of the array.\nThe relative ordering of the elements less than and greater than pivot is also maintained. [9, 5, 3] and [12, 14] are the respective orderings.\n\n\n
Example 2:
\n\n\nInput: nums = [-3,4,3,2], pivot = 2\nOutput: [-3,2,4,3]\nExplanation: \nThe element -3 is less than the pivot so it is on the left side of the array.\nThe elements 4 and 3 are greater than the pivot so they are on the right side of the array.\nThe relative ordering of the elements less than and greater than pivot is also maintained. [-3] and [4, 3] are the respective orderings.\n\n\n
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Constraints:
\n\n1 <= nums.length <= 105-106 <= nums[i] <= 106pivot equals to an element of nums.给你一个下标从 0 开始的整数数组 nums 和一个整数 pivot 。请你将 nums 重新排列，使得以下条件均成立：
pivot 的元素都出现在所有大于 pivot 的元素 之前 。pivot 的元素都出现在小于和大于 pivot 的元素 中间 。pivot 的元素之间和大于 pivot 的元素之间的 相对顺序 不发生改变。\n\tpi，pj ，pi 是初始时位置 i 元素的新位置，pj 是初始时位置 j 元素的新位置。对于小于 pivot 的元素，如果 i < j 且 nums[i] < pivot 和 nums[j] < pivot 都成立，那么 pi < pj 也成立。类似的，对于大于 pivot 的元素，如果 i < j 且 nums[i] > pivot 和 nums[j] > pivot 都成立，那么 pi < pj 。请你返回重新排列 nums 数组后的结果数组。
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示例 1：
\n\n输入：nums = [9,12,5,10,14,3,10], pivot = 10\n输出：[9,5,3,10,10,12,14]\n解释：\n元素 9 ，5 和 3 小于 pivot ，所以它们在数组的最左边。\n元素 12 和 14 大于 pivot ，所以它们在数组的最右边。\n小于 pivot 的元素的相对位置和大于 pivot 的元素的相对位置分别为 [9, 5, 3] 和 [12, 14] ，它们在结果数组中的相对顺序需要保留。\n\n\n
示例 2：
\n\n输入：nums = [-3,4,3,2], pivot = 2\n输出：[-3,2,4,3]\n解释：\n元素 -3 小于 pivot ，所以在数组的最左边。\n元素 4 和 3 大于 pivot ，所以它们在数组的最右边。\n小于 pivot 的元素的相对位置和大于 pivot 的元素的相对位置分别为 [-3] 和 [4, 3] ，它们在结果数组中的相对顺序需要保留。\n\n\n
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提示：
\n\n1 <= nums.length <= 105-106 <= nums[i] <= 106pivot 等于 nums 中的一个元素。\\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\"],\"java\":[\"Java\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u88ab\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5305\\u542b Pair \\u7c7b: https:\\/\\/docs.oracle.com\\/javase\\/8\\/javafx\\/api\\/javafx\\/util\\/Pair.html <\\/p>\"],\"python\":[\"Python\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982\\uff1aarray<\\/a>, bisect<\\/a>, 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