{ "data": { "question": { "questionId": "3192", "questionFrontendId": "2939", "categoryTitle": "Algorithms", "boundTopicId": 2529055, "title": "Maximum Xor Product", "titleSlug": "maximum-xor-product", "content": "
Given three integers a
, b
, and n
, return the maximum value of (a XOR x) * (b XOR x)
where 0 <= x < 2n
.
Since the answer may be too large, return it modulo 109 + 7
.
Note that XOR
is the bitwise XOR operation.
\n
Example 1:
\n\n\nInput: a = 12, b = 5, n = 4\nOutput: 98\nExplanation: For x = 2, (a XOR x) = 14 and (b XOR x) = 7. Hence, (a XOR x) * (b XOR x) = 98. \nIt can be shown that 98 is the maximum value of (a XOR x) * (b XOR x) for all 0 <= x < 2n.\n
\n\nExample 2:
\n\n\nInput: a = 6, b = 7 , n = 5\nOutput: 930\nExplanation: For x = 25, (a XOR x) = 31 and (b XOR x) = 30. Hence, (a XOR x) * (b XOR x) = 930.\nIt can be shown that 930 is the maximum value of (a XOR x) * (b XOR x) for all 0 <= x < 2n.\n\n
Example 3:
\n\n\nInput: a = 1, b = 6, n = 3\nOutput: 12\nExplanation: For x = 5, (a XOR x) = 4 and (b XOR x) = 3. Hence, (a XOR x) * (b XOR x) = 12.\nIt can be shown that 12 is the maximum value of (a XOR x) * (b XOR x) for all 0 <= x < 2n.\n\n\n
\n
Constraints:
\n\n0 <= a, b < 250
0 <= n <= 50
给你三个整数 a
,b
和 n
,请你返回 (a XOR x) * (b XOR x)
的 最大值 且 x
需要满足 0 <= x < 2n
。
由于答案可能会很大,返回它对 109 + 7
取余 后的结果。
注意,XOR
是按位异或操作。
\n\n
示例 1:
\n\n\n输入:a = 12, b = 5, n = 4\n输出:98\n解释:当 x = 2 时,(a XOR x) = 14 且 (b XOR x) = 7 。所以,(a XOR x) * (b XOR x) = 98 。\n98 是所有满足 0 <= x < 2n 中 (a XOR x) * (b XOR x) 的最大值。\n\n\n
示例 2:
\n\n\n输入:a = 6, b = 7 , n = 5\n输出:930\n解释:当 x = 25 时,(a XOR x) = 31 且 (b XOR x) = 30 。所以,(a XOR x) * (b XOR x) = 930 。\n930 是所有满足 0 <= x < 2n 中 (a XOR x) * (b XOR x) 的最大值。\n\n
示例 3:
\n\n\n输入:a = 1, b = 6, n = 3\n输出:12\n解释: 当 x = 5 时,(a XOR x) = 4 且 (b XOR x) = 3 。所以,(a XOR x) * (b XOR x) = 12 。\n12 是所有满足 0 <= x < 2n 中 (a XOR x) * (b XOR x) 的最大值。\n\n\n
\n\n
提示:
\n\n0 <= a, b < 250
0 <= n <= 50
ith
bit, if both a
and b
have the same value, we can always make x
’s ith
bit different from a
and b
, so a ^ x
and b ^ x
both have the ith bit set.",
"Otherwise, we can only set the ith
bit of one of a ^ x
or b ^ x
. Depending on the previous bits of a ^ x
or b ^ x
, we should set the smaller value’s ith
bit."
],
"solution": null,
"status": null,
"sampleTestCase": "12\n5\n4",
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