{ "data": { "question": { "questionId": "2605", "questionFrontendId": "2514", "categoryTitle": "Algorithms", "boundTopicId": 2029982, "title": "Count Anagrams", "titleSlug": "count-anagrams", "content": "

You are given a string s containing one or more words. Every consecutive pair of words is separated by a single space ' '.

\n\n

A string t is an anagram of string s if the ith word of t is a permutation of the ith word of s.

\n\n\n\n

Return the number of distinct anagrams of s. Since the answer may be very large, return it modulo 109 + 7.

\n\n

 

\n

Example 1:

\n\n
\nInput: s = "too hot"\nOutput: 18\nExplanation: Some of the anagrams of the given string are "too hot", "oot hot", "oto toh", "too toh", and "too oht".\n
\n\n

Example 2:

\n\n
\nInput: s = "aa"\nOutput: 1\nExplanation: There is only one anagram possible for the given string.
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "统计同位异构字符串数目", "translatedContent": "

给你一个字符串 s ，它包含一个或者多个单词。单词之间用单个空格 ' ' 隔开。

\n\n

如果字符串 t 中第 i 个单词是 s 中第 i 个单词的一个 排列 ，那么我们称字符串 t 是字符串 s 的同位异构字符串。

\n\n\n\n

请你返回 s 的同位异构字符串的数目，由于答案可能很大，请你将它对 109 + 7 取余 后返回。

\n\n

 

\n\n

示例 1：

\n\n
输入：s = \"too hot\"\n输出：18\n解释：输入字符串的一些同位异构字符串为 \"too hot\" ，\"oot hot\" ，\"oto toh\" ，\"too toh\" 以及 \"too oht\" 。\n
\n\n

示例 2：

\n\n
输入：s = \"aa\"\n输出：1\n解释：输入字符串只有一个同位异构字符串。
\n\n

 

\n\n

提示：

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