You are given an integer array nums and an integer k.
For each index i where 0 <= i < nums.length, change nums[i] to be either nums[i] + k or nums[i] - k.
The score of nums is the difference between the maximum and minimum elements in nums.
Return the minimum score of nums after changing the values at each index.
\n
Example 1:
\n\n\nInput: nums = [1], k = 0\nOutput: 0\nExplanation: The score is max(nums) - min(nums) = 1 - 1 = 0.\n\n\n
Example 2:
\n\n\nInput: nums = [0,10], k = 2\nOutput: 6\nExplanation: Change nums to be [2, 8]. The score is max(nums) - min(nums) = 8 - 2 = 6.\n\n\n
Example 3:
\n\n\nInput: nums = [1,3,6], k = 3\nOutput: 3\nExplanation: Change nums to be [4, 6, 3]. The score is max(nums) - min(nums) = 6 - 3 = 3.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1040 <= nums[i] <= 1040 <= k <= 104给你一个整数数组 nums，和一个整数 k 。
对于每个下标 i（0 <= i < nums.length），将 nums[i] 变成 nums[i] + k 或 nums[i] - k 。
nums 的 分数 是 nums 中最大元素和最小元素的差值。
在更改每个下标对应的值之后，返回 nums 的最小 分数 。
\n\n
示例 1：
\n\n\n输入：nums = [1], k = 0\n输出：0\n解释：分数 = max(nums) - min(nums) = 1 - 1 = 0 。\n\n\n
示例 2：
\n\n\n输入：nums = [0,10], k = 2\n输出：6\n解释：将数组变为 [2, 8] 。分数 = max(nums) - min(nums) = 8 - 2 = 6 。\n\n\n
示例 3：
\n\n\n输入：nums = [1,3,6], k = 3\n输出：3\n解释：将数组变为 [4, 6, 3] 。分数 = max(nums) - min(nums) = 6 - 3 = 3 。\n\n\n
\n\n
提示：
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