{ "data": { "question": { "questionId": "2733", "questionFrontendId": "2621", "categoryTitle": "JavaScript", "boundTopicId": 2222274, "title": "Sleep", "titleSlug": "sleep", "content": "
Given a positive integer millis
, write an asynchronous function that sleeps for millis
milliseconds. It can resolve any value.
Note that minor deviation from millis
in the actual sleep duration is acceptable.
\n
Example 1:
\n\n\nInput: millis = 100\nOutput: 100\nExplanation: It should return a promise that resolves after 100ms.\nlet t = Date.now();\nsleep(100).then(() => {\n console.log(Date.now() - t); // 100\n});\n\n\n
Example 2:
\n\n\nInput: millis = 200\nOutput: 200\nExplanation: It should return a promise that resolves after 200ms.\n\n\n
\n
Constraints:
\n\n1 <= millis <= 1000
请你编写一个异步函数,它接收一个正整数参数 millis
,并休眠 millis
毫秒。要求此函数可以解析任何值。
请注意,实际睡眠持续时间与 millis
之间的微小偏差是可以接受的。
\n\n
示例 1:
\n\n\n输入:millis = 100\n输出:100\n解释:\n在 100ms 后此异步函数执行完时返回一个 Promise 对象\nlet t = Date.now();\nsleep(100).then(() => {\n console.log(Date.now() - t); // 100\n});\n\n\n
示例 2:
\n\n\n输入:millis = 200\n输出:200\n解释:在 200ms 后函数执行完时返回一个 Promise 对象\n\n\n
\n\n
提示:
\n\n1 <= millis <= 1000
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