{ "data": { "question": { "questionId": "73", "questionFrontendId": "73", "categoryTitle": "Algorithms", "boundTopicId": 1671, "title": "Set Matrix Zeroes", "titleSlug": "set-matrix-zeroes", "content": "

Given an m x n integer matrix matrix, if an element is 0, set its entire row and column to 0's.

\n\n

You must do it in place.

\n\n

 

\n

Example 1:

\n\"\"\n
\nInput: matrix = [[1,1,1],[1,0,1],[1,1,1]]\nOutput: [[1,0,1],[0,0,0],[1,0,1]]\n
\n\n

Example 2:

\n\"\"\n
\nInput: matrix = [[0,1,2,0],[3,4,5,2],[1,3,1,5]]\nOutput: [[0,0,0,0],[0,4,5,0],[0,3,1,0]]\n
\n\n

 

\n

Constraints:

\n\n\n\n

 

\n

Follow up:

\n\n\n", "translatedTitle": "矩阵置零", "translatedContent": "

给定一个 m x n 的矩阵，如果一个元素为 0 ，则将其所在行和列的所有元素都设为 0 。请使用 原地 算法。

\n\n\n\n

 

\n\n

示例 1：

\n\"\"\n
\n输入：matrix = [[1,1,1],[1,0,1],[1,1,1]]\n输出：[[1,0,1],[0,0,0],[1,0,1]]\n
\n\n

示例 2：

\n\"\"\n
\n输入：matrix = [[0,1,2,0],[3,4,5,2],[1,3,1,5]]\n输出：[[0,0,0,0],[0,4,5,0],[0,3,1,0]]\n
\n\n

 

\n\n

提示：

\n\n\n\n

 

\n\n

进阶：

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{ "name": "Matrix", "slug": "matrix", "translatedName": "矩阵", "__typename": "TopicTagNode" } ], "companyTagStats": null, "codeSnippets": [ { "lang": "C++", "langSlug": "cpp", "code": "class Solution {\npublic:\n void setZeroes(vector>& matrix) {\n \n }\n};", "__typename": "CodeSnippetNode" }, { "lang": "Java", "langSlug": "java", "code": "class Solution {\n public void setZeroes(int[][] matrix) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Python3", "langSlug": "python3", "code": "class Solution:\n def setZeroes(self, matrix: List[List[int]]) -> None:\n \"\"\"\n Do not return anything, modify matrix in-place instead.\n \"\"\"\n ", "__typename": "CodeSnippetNode" }, { "lang": "Python", "langSlug": "python", "code": "class Solution(object):\n def setZeroes(self, matrix):\n \"\"\"\n :type matrix: List[List[int]]\n :rtype: None Do not return anything, modify matrix in-place instead.\n \"\"\"\n ", "__typename": "CodeSnippetNode" }, { "lang": "JavaScript", "langSlug": "javascript", "code": "/**\n * @param {number[][]} matrix\n * @return {void} Do not return anything, modify matrix in-place instead.\n */\nvar setZeroes = function(matrix) {\n \n};", "__typename": "CodeSnippetNode" }, { "lang": "TypeScript", "langSlug": "typescript", "code": "/**\n Do not return anything, modify matrix in-place instead.\n */\nfunction setZeroes(matrix: number[][]): void {\n \n};", "__typename": "CodeSnippetNode" }, { "lang": "C#", "langSlug": "csharp", "code": "public class Solution {\n public void SetZeroes(int[][] matrix) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "C", "langSlug": "c", "code": "void setZeroes(int** matrix, int matrixSize, int* matrixColSize) {\n \n}", "__typename": "CodeSnippetNode" }, { "lang": "Go", "langSlug": "golang", "code": "func setZeroes(matrix [][]int) {\n \n}", "__typename": "CodeSnippetNode" }, { "lang": "Kotlin", "langSlug": "kotlin", "code": "class Solution {\n fun setZeroes(matrix: Array): Unit {\n \n }\n}", 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Array[Array[Int]]): Unit = {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Cangjie", "langSlug": "cangjie", "code": "class Solution {\n func setZeroes(matrix: Array>): Unit {\n\n }\n}", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"638.4K\", \"totalSubmission\": \"896.8K\", \"totalAcceptedRaw\": 638389, \"totalSubmissionRaw\": 896795, \"acRate\": \"71.2%\"}", "hints": [ "If any cell of the matrix has a zero we can record its row and column number using additional memory.\r\nBut if you don't want to use extra memory then you can manipulate the array instead. i.e. simulating exactly what the question says.", "Setting cell values to zero on the fly while iterating might lead to discrepancies. 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