{ "data": { "question": { "questionId": "268", "questionFrontendId": "268", "categoryTitle": "Algorithms", "boundTopicId": 1343, "title": "Missing Number", "titleSlug": "missing-number", "content": "

Given an array nums containing n distinct numbers in the range [0, n], return the only number in the range that is missing from the array.

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Example 1:

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Input: nums = [3,0,1]

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Output: 2

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Explanation:

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n = 3 since there are 3 numbers, so all numbers are in the range [0,3]. 2 is the missing number in the range since it does not appear in nums.

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Example 2:

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Input: nums = [0,1]

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Output: 2

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Explanation:

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n = 2 since there are 2 numbers, so all numbers are in the range [0,2]. 2 is the missing number in the range since it does not appear in nums.

\n
\n\n

Example 3:

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\n

Input: nums = [9,6,4,2,3,5,7,0,1]

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Output: 8

\n\n

Explanation:

\n\n

n = 9 since there are 9 numbers, so all numbers are in the range [0,9]. 8 is the missing number in the range since it does not appear in nums.

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\n
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Constraints:

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Follow up: Could you implement a solution using only O(1) extra space complexity and O(n) runtime complexity?

\n", "translatedTitle": "丢失的数字", "translatedContent": "

给定一个包含 [0, n] 中 n 个数的数组 nums ,找出 [0, n] 这个范围内没有出现在数组中的那个数。

\n\n\n\n

 

\n\n

示例 1:

\n\n
\n

输入:nums = [3,0,1]

\n\n

输出:2

\n\n

解释:n = 3,因为有 3 个数字,所以所有的数字都在范围 [0,3] 内。2 是丢失的数字,因为它没有出现在 nums 中。

\n
\n\n

示例 2:

\n\n
\n

输入:nums = [0,1]

\n\n

输出:2

\n\n

解释:n = 2,因为有 2 个数字,所以所有的数字都在范围 [0,2] 内。2 是丢失的数字,因为它没有出现在 nums 中。

\n
\n\n

示例 3:

\n\n
\n

输入:nums = [9,6,4,2,3,5,7,0,1]

\n\n

输出:8

\n\n

解释:n = 9,因为有 9 个数字,所以所有的数字都在范围 [0,9] 内。8 是丢失的数字,因为它没有出现在 nums 中。

\n
\n\n

提示:

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进阶:你能否实现线性时间复杂度、仅使用额外常数空间的算法解决此问题?

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