{ "data": { "question": { "questionId": "1826", "questionFrontendId": "1707", "categoryTitle": "Algorithms", "boundTopicId": 533210, "title": "Maximum XOR With an Element From Array", "titleSlug": "maximum-xor-with-an-element-from-array", "content": "

You are given an array nums consisting of non-negative integers. You are also given a queries array, where queries[i] = [xi, mi].

\n\n

The answer to the ith query is the maximum bitwise XOR value of xi and any element of nums that does not exceed mi. In other words, the answer is max(nums[j] XOR xi) for all j such that nums[j] <= mi. If all elements in nums are larger than mi, then the answer is -1.

\n\n

Return an integer array answer where answer.length == queries.length and answer[i] is the answer to the ith query.

\n\n

 

\n

Example 1:

\n\n
\nInput: nums = [0,1,2,3,4], queries = [[3,1],[1,3],[5,6]]\nOutput: [3,3,7]\nExplanation:\n1) 0 and 1 are the only two integers not greater than 1. 0 XOR 3 = 3 and 1 XOR 3 = 2. The larger of the two is 3.\n2) 1 XOR 2 = 3.\n3) 5 XOR 2 = 7.\n
\n\n

Example 2:

\n\n
\nInput: nums = [5,2,4,6,6,3], queries = [[12,4],[8,1],[6,3]]\nOutput: [15,-1,5]\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "与数组中元素的最大异或值", "translatedContent": "

给你一个由非负整数组成的数组 nums 。另有一个查询数组 queries ,其中 queries[i] = [xi, mi]

\n\n

i 个查询的答案是 xi 和任何 nums 数组中不超过 mi 的元素按位异或(XOR)得到的最大值。换句话说,答案是 max(nums[j] XOR xi) ,其中所有 j 均满足 nums[j] <= mi 。如果 nums 中的所有元素都大于 mi,最终答案就是 -1

\n\n

返回一个整数数组 answer 作为查询的答案,其中 answer.length == queries.length answer[i] 是第 i 个查询的答案。

\n\n

 

\n\n

示例 1:

\n\n
输入:nums = [0,1,2,3,4], queries = [[3,1],[1,3],[5,6]]\n输出:[3,3,7]\n解释:\n1) 0 和 1 是仅有的两个不超过 1 的整数。0 XOR 3 = 3 而 1 XOR 3 = 2 。二者中的更大值是 3 。\n2) 1 XOR 2 = 3.\n3) 5 XOR 2 = 7.\n
\n\n

示例 2:

\n\n
输入:nums = [5,2,4,6,6,3], queries = [[12,4],[8,1],[6,3]]\n输出:[15,-1,5]\n
\n\n

 

\n\n

提示:

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nums: List[int]\n :type queries: List[List[int]]\n :rtype: List[int]\n \"\"\"\n ", "__typename": "CodeSnippetNode" }, { "lang": "JavaScript", "langSlug": "javascript", "code": "/**\n * @param {number[]} nums\n * @param {number[][]} queries\n * @return {number[]}\n */\nvar maximizeXor = function(nums, queries) {\n \n};", "__typename": "CodeSnippetNode" }, { "lang": "TypeScript", "langSlug": "typescript", "code": "function maximizeXor(nums: number[], queries: number[][]): number[] {\n \n};", "__typename": "CodeSnippetNode" }, { "lang": "C#", "langSlug": "csharp", "code": "public class Solution {\n public int[] MaximizeXor(int[] nums, int[][] queries) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "C", "langSlug": "c", "code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* maximizeXor(int* nums, int numsSize, int** queries, int queriesSize, int* queriesColSize, int* returnSize) {\n \n}", "__typename": "CodeSnippetNode" }, { "lang": 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@return Integer[]\n */\n function maximizeXor($nums, $queries) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Dart", "langSlug": "dart", "code": "class Solution {\n List maximizeXor(List nums, List> queries) {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Scala", "langSlug": "scala", "code": "object Solution {\n def maximizeXor(nums: Array[Int], queries: Array[Array[Int]]): Array[Int] = {\n \n }\n}", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "defmodule Solution do\n @spec maximize_xor(nums :: [integer], queries :: [[integer]]) :: [integer]\n def maximize_xor(nums, queries) do\n \n end\nend", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec maximize_xor(Nums :: [integer()], Queries :: [[integer()]]) -> [integer()].\nmaximize_xor(Nums, Queries) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Racket", "langSlug": "racket", "code": "(define/contract (maximize-xor nums queries)\n (-> (listof exact-integer?) (listof (listof exact-integer?)) (listof exact-integer?))\n )", "__typename": "CodeSnippetNode" }, { "lang": "Cangjie", "langSlug": "cangjie", "code": "class Solution {\n func maximizeXor(nums: Array, queries: Array>): Array {\n\n }\n}", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"18.4K\", \"totalSubmission\": \"35.8K\", \"totalAcceptedRaw\": 18362, \"totalSubmissionRaw\": 35761, \"acRate\": \"51.3%\"}", "hints": [ "In problems involving bitwise operations, we often think on the bits level. In this problem, we can think that to maximize the result of an xor operation, we need to maximize the most significant bit, then the next one, and so on.", "If there's some number in the array that is less than m and whose the most significant bit is different than that of x, then xoring with this number maximizes the most significant bit, so I know this bit in the answer is 1.", "To check the existence of such numbers and narrow your scope for further bits based on your choice, you can use trie.", "You can sort the array and the queries, and maintain the trie such that in each query the trie consists exactly of the valid elements." ], "solution": null, "status": null, "sampleTestCase": "[0,1,2,3,4]\n[[3,1],[1,3],[5,6]]", "metaData": "{\n \"name\": \"maximizeXor\",\n \"params\": [\n {\n \"name\": \"nums\",\n \"type\": \"integer[]\"\n },\n {\n \"type\": \"integer[][]\",\n \"name\": \"queries\"\n }\n ],\n \"return\": {\n \"type\": \"integer[]\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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