You are given an array of integers nums of size 3.
Return the maximum possible number whose binary representation can be formed by concatenating the binary representation of all elements in nums in some order.
Note that the binary representation of any number does not contain leading zeros.
\n\n\n
Example 1:
\n\nInput: nums = [1,2,3]
\n\nOutput: 30
\n\nExplanation:
\n\nConcatenate the numbers in the order [3, 1, 2] to get the result "11110", which is the binary representation of 30.
Example 2:
\n\nInput: nums = [2,8,16]
\n\nOutput: 1296
\n\nExplanation:
\n\nConcatenate the numbers in the order [2, 8, 16] to get the result "10100010000", which is the binary representation of 1296.
\n
Constraints:
\n\nnums.length == 31 <= nums[i] <= 127给你一个长度为 3 的整数数组 nums。
现以某种顺序 连接 数组 nums 中所有元素的 二进制表示 ，请你返回可以由这种方法形成的 最大 数值。
注意 任何数字的二进制表示 不含 前导零。
\n\n\n\n
示例 1:
\n\n输入: nums = [1,2,3]
\n\n输出: 30
\n\n解释:
\n\n按照顺序 [3, 1, 2] 连接数字的二进制表示，得到结果 \"11110\"，这是 30 的二进制表示。
示例 2:
\n\n输入: nums = [2,8,16]
\n\n输出: 1296
\n\n解释:
\n\n按照顺序 [2, 8, 16] 连接数字的二进制表述，得到结果 \"10100010000\"，这是 1296 的二进制表示。
\n\n
提示:
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