Given an array nums of n integers where nums[i] is in the range [1, n], return an array of all the integers in the range [1, n] that do not appear in nums.
\n
Example 1:
\nInput: nums = [4,3,2,7,8,2,3,1]\nOutput: [5,6]\n
Example 2:
\nInput: nums = [1,1]\nOutput: [2]\n\n
\n
Constraints:
\n\nn == nums.length1 <= n <= 1051 <= nums[i] <= n\n
Follow up: Could you do it without extra space and in O(n) runtime? You may assume the returned list does not count as extra space.
给你一个含 n 个整数的数组 nums ，其中 nums[i] 在区间 [1, n] 内。请你找出所有在 [1, n] 范围内但没有出现在 nums 中的数字，并以数组的形式返回结果。
\n\n
示例 1：
\n\n\n输入：nums = [4,3,2,7,8,2,3,1]\n输出：[5,6]\n\n\n
示例 2：
\n\n\n输入：nums = [1,1]\n输出：[2]\n\n\n
\n\n
提示：
\n\nn == nums.length1 <= n <= 1051 <= nums[i] <= n进阶：你能在不使用额外空间且时间复杂度为 O(n) 的情况下解决这个问题吗? 你可以假定返回的数组不算在额外空间内。
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