You are given two strings s1 and s2 of equal length. A string swap is an operation where you choose two indices in a string (not necessarily different) and swap the characters at these indices.
Return true if it is possible to make both strings equal by performing at most one string swap on exactly one of the strings. Otherwise, return false.
\n
Example 1:
\n\n\nInput: s1 = "bank", s2 = "kanb"\nOutput: true\nExplanation: For example, swap the first character with the last character of s2 to make "bank".\n\n\n
Example 2:
\n\n\nInput: s1 = "attack", s2 = "defend"\nOutput: false\nExplanation: It is impossible to make them equal with one string swap.\n\n\n
Example 3:
\n\n\nInput: s1 = "kelb", s2 = "kelb"\nOutput: true\nExplanation: The two strings are already equal, so no string swap operation is required.\n\n\n
\n
Constraints:
\n\n1 <= s1.length, s2.length <= 100s1.length == s2.lengths1 and s2 consist of only lowercase English letters.给你长度相等的两个字符串 s1 和 s2 。一次 字符串交换 操作的步骤如下：选出某个字符串中的两个下标（不必不同），并交换这两个下标所对应的字符。
如果对 其中一个字符串 执行 最多一次字符串交换 就可以使两个字符串相等，返回 true ；否则，返回 false 。
\n\n
示例 1：
\n\n输入：s1 = \"bank\", s2 = \"kanb\"\n输出：true\n解释：例如，交换 s2 中的第一个和最后一个字符可以得到 \"bank\"\n\n\n
示例 2：
\n\n输入：s1 = \"attack\", s2 = \"defend\"\n输出：false\n解释：一次字符串交换无法使两个字符串相等\n\n\n
示例 3：
\n\n输入：s1 = \"kelb\", s2 = \"kelb\"\n输出：true\n解释：两个字符串已经相等，所以不需要进行字符串交换\n\n\n
示例 4：
\n\n输入：s1 = \"abcd\", s2 = \"dcba\"\n输出：false\n\n\n
\n\n
提示：
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"book": null,
"isSubscribed": false,
"isDailyQuestion": false,
"dailyRecordStatus": null,
"editorType": "CKEDITOR",
"ugcQuestionId": null,
"style": "LEETCODE",
"exampleTestcases": "\"bank\"\n\"kanb\"\n\"attack\"\n\"defend\"\n\"kelb\"\n\"kelb\"",
"__typename": "QuestionNode"
}
}
}clang 19<\\/code> \\u91c7\\u7528\\u6700\\u65b0 C++ 23 \\u6807\\u51c6\\uff0c\\u5e76\\u4f7f\\u7528 GCC 14 \\u63d0\\u4f9b\\u7684 libstdc++<\\/code>\\u3002<\\/p>\\r\\n\\r\\n-O2<\\/code> \\u7ea7\\u4f18\\u5316\\uff0c\\u5e76\\u63d0\\u4f9b -gline-tables-only<\\/code> \\u53c2\\u6570\\u3002AddressSanitizer<\\/a> \\u4e5f\\u88ab\\u5f00\\u542f\\u6765\\u68c0\\u6d4b out-of-bounds<\\/code> \\u548c use-after-free<\\/code> \\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\nOpenJDK 21<\\/code>\\u3002\\u4f7f\\u7528\\u7f16\\u8bd1\\u53c2\\u6570 --enable-preview --release 21<\\/code><\\/p>\\r\\n\\r\\nPython 2.7.18<\\/code><\\/p>\\r\\n\\r\\nGCC 14<\\/code>\\uff0c\\u91c7\\u7528 GNU11 \\u6807\\u51c6\\u3002<\\/p>\\r\\n\\r\\n-O2<\\/code> \\u7ea7\\u4f18\\u5316\\uff0c\\u5e76\\u63d0\\u4f9b -g1<\\/code> \\u53c2\\u6570\\u3002 AddressSanitizer<\\/a> \\u4e5f\\u88ab\\u5f00\\u542f\\u6765\\u68c0\\u6d4b out-of-bounds<\\/code> \\u548c use-after-free<\\/code> \\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n\\r\\nstruct hash_entry {\\r\\n int id; \\/* we'll use this field as the key *\\/\\r\\n char name[10];\\r\\n UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n\\r\\nstruct hash_entry *find_user(int user_id) {\\r\\n struct hash_entry *s;\\r\\n HASH_FIND_INT(users, &user_id, s);\\r\\n return s;\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n\\r\\nvoid delete_user(struct hash_entry *user) {\\r\\n HASH_DEL(users, user); \\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\"],\"csharp\":[\"C#\",\"Node.js 22.14.0<\\/code><\\/p>\\r\\n\\r\\n--harmony<\\/code> \\u6807\\u8bb0\\u6765\\u5f00\\u542f \\u65b0\\u7248ES6\\u7279\\u6027<\\/a>\\u3002<\\/p>\\r\\n\\r\\nRuby 3.2<\\/code> \\u6267\\u884c<\\/p>\\r\\n\\r\\nSwift 6.0<\\/code><\\/p>\\r\\n\\r\\nGo 1.23<\\/code><\\/p>\\r\\n\\r\\nPython 3.11<\\/code><\\/p>\\r\\n\\r\\nScala 3.3.1<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"Kotlin 2.1.10<\\/code><\\/p>\"],\"rust\":[\"Rust\",\"rust 1.88.0<\\/code>\\uff0c\\u4f7f\\u7528 edition 2024\\u3002<\\/p>\\r\\n\\r\\nPHP 8.2<\\/code>.<\\/p>\\r\\n\\r\\n-O2 --disable-reflection<\\/code><\\/p>\\r\\n\\r\\n