You are given a positive integer arrivalTime denoting the arrival time of a train in hours, and another positive integer delayedTime denoting the amount of delay in hours.
Return the time when the train will arrive at the station.
\n\nNote that the time in this problem is in 24-hours format.
\n\n\n
Example 1:
\n\n\nInput: arrivalTime = 15, delayedTime = 5 \nOutput: 20 \nExplanation: Arrival time of the train was 15:00 hours. It is delayed by 5 hours. Now it will reach at 15+5 = 20 (20:00 hours).\n\n\n
Example 2:
\n\n\nInput: arrivalTime = 13, delayedTime = 11\nOutput: 0\nExplanation: Arrival time of the train was 13:00 hours. It is delayed by 11 hours. Now it will reach at 13+11=24 (Which is denoted by 00:00 in 24 hours format so return 0).\n\n\n
\n
Constraints:
\n\n1 <= arrivaltime < 241 <= delayedTime <= 24给你一个正整数 arrivalTime 表示列车正点到站的时间（单位：小时），另给你一个正整数 delayedTime 表示列车延误的小时数。
返回列车实际到站的时间。
\n\n注意，该问题中的时间采用 24 小时制。
\n\n\n\n
示例 1：
\n\n输入：arrivalTime = 15, delayedTime = 5 \n输出：20 \n解释：列车正点到站时间是 15:00 ，延误 5 小时，所以列车实际到站的时间是 15 + 5 = 20（20:00）。\n\n\n
示例 2：
\n\n输入：arrivalTime = 13, delayedTime = 11\n输出：0\n解释：列车正点到站时间是 13:00 ，延误 11 小时，所以列车实际到站的时间是 13 + 11 = 24（在 24 小时制中表示为 00:00 ，所以返回 0）。\n\n
\n\n
提示：
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