You are given a 0-indexed integer array nums. You are also given an integer key, which is present in nums.
For every unique integer target in nums, count the number of times target immediately follows an occurrence of key in nums. In other words, count the number of indices i such that:
0 <= i <= nums.length - 2,nums[i] == key and,nums[i + 1] == target.Return the target with the maximum count. The test cases will be generated such that the target with maximum count is unique.
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Example 1:
\n\n\nInput: nums = [1,100,200,1,100], key = 1\nOutput: 100\nExplanation: For target = 100, there are 2 occurrences at indices 1 and 4 which follow an occurrence of key.\nNo other integers follow an occurrence of key, so we return 100.\n\n\n
Example 2:
\n\n\nInput: nums = [2,2,2,2,3], key = 2\nOutput: 2\nExplanation: For target = 2, there are 3 occurrences at indices 1, 2, and 3 which follow an occurrence of key.\nFor target = 3, there is only one occurrence at index 4 which follows an occurrence of key.\ntarget = 2 has the maximum number of occurrences following an occurrence of key, so we return 2.\n\n\n
\n
Constraints:
\n\n2 <= nums.length <= 10001 <= nums[i] <= 1000Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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