You are given a 0-indexed integer array nums of length n.
We want to group the indices so for each index i in the range [0, n - 1], it is assigned to exactly one group.
A group assignment is valid if the following conditions hold:
\n\ng, all indices i assigned to group g have the same value in nums.g1 and g2, the difference between the number of indices assigned to g1 and g2 should not exceed 1.Return an integer denoting the minimum number of groups needed to create a valid group assignment.
\n\n\n
Example 1:
\n\n\nInput: nums = [3,2,3,2,3]\nOutput: 2\nExplanation: One way the indices can be assigned to 2 groups is as follows, where the values in square brackets are indices:\ngroup 1 -> [0,2,4]\ngroup 2 -> [1,3]\nAll indices are assigned to one group.\nIn group 1, nums[0] == nums[2] == nums[4], so all indices have the same value.\nIn group 2, nums[1] == nums[3], so all indices have the same value.\nThe number of indices assigned to group 1 is 3, and the number of indices assigned to group 2 is 2.\nTheir difference doesn't exceed 1.\nIt is not possible to use fewer than 2 groups because, in order to use just 1 group, all indices assigned to that group must have the same value.\nHence, the answer is 2.\n\n
Example 2:
\n\n\nInput: nums = [10,10,10,3,1,1]\nOutput: 4\nExplanation: One way the indices can be assigned to 4 groups is as follows, where the values in square brackets are indices:\ngroup 1 -> [0]\ngroup 2 -> [1,2]\ngroup 3 -> [3]\ngroup 4 -> [4,5]\nThe group assignment above satisfies both conditions.\nIt can be shown that it is not possible to create a valid assignment using fewer than 4 groups.\nHence, the answer is 4.\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1051 <= nums[i] <= 109x in the range [1, minimum_frequency], try to create groups with either x or x + 1 indices assigned to them while minimizing the total number of groups.",
"For each distinct number, using its frequency, check that all its occurrences can be assigned to groups of size x or x + 1 while minimizing the number of groups used.",
"To get the minimum number of groups needed for a number having frequency f to be assigned to groups of size x or x + 1, let a = f / (x + 1) and b = f % (x + 1). b == 0, then we can simply create a groups of size x + 1.x - b <= a, we can have a - (x - b) groups of size x + 1 and x - b + 1 groups of size x. So, in total, we have a + 1 groups.x is the total minimized number of groups needed for each distinct number.",
"The answer is the minimum number of groups needed for each x in the range [1, minimum_frequency]."
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