Given two arrays of strings list1 and list2, find the common strings with the least index sum.
A common string is a string that appeared in both list1 and list2.
A common string with the least index sum is a common string such that if it appeared at list1[i] and list2[j] then i + j should be the minimum value among all the other common strings.
Return all the common strings with the least index sum. Return the answer in any order.
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Example 1:
\n\n\nInput: list1 = ["Shogun","Tapioca Express","Burger King","KFC"], list2 = ["Piatti","The Grill at Torrey Pines","Hungry Hunter Steakhouse","Shogun"]\nOutput: ["Shogun"]\nExplanation: The only common string is "Shogun".\n\n\n
Example 2:
\n\n\nInput: list1 = ["Shogun","Tapioca Express","Burger King","KFC"], list2 = ["KFC","Shogun","Burger King"]\nOutput: ["Shogun"]\nExplanation: The common string with the least index sum is "Shogun" with index sum = (0 + 1) = 1.\n\n\n
Example 3:
\n\n\nInput: list1 = ["happy","sad","good"], list2 = ["sad","happy","good"]\nOutput: ["sad","happy"]\nExplanation: There are three common strings:\n"happy" with index sum = (0 + 1) = 1.\n"sad" with index sum = (1 + 0) = 1.\n"good" with index sum = (2 + 2) = 4.\nThe strings with the least index sum are "sad" and "happy".\n\n\n
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Constraints:
\n\n1 <= list1.length, list2.length <= 10001 <= list1[i].length, list2[i].length <= 30list1[i] and list2[i] consist of spaces ' ' and English letters.list1 are unique.list2 are unique.list1 and list2.Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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