You are given a 0-indexed binary string s of length n on which you can apply two types of operations:
i and invert all characters from index 0 to index i (both inclusive), with a cost of i + 1i and invert all characters from index i to index n - 1 (both inclusive), with a cost of n - iReturn the minimum cost to make all characters of the string equal.
\n\nInvert a character means if its value is '0' it becomes '1' and vice-versa.
\n\n\n
Example 1:
\n\n\nInput: s = "0011"\nOutput: 2\nExplanation: Apply the second operation with\n\ni = 2to obtains = "0000" for a cost of 2. It can be shown that 2 is the minimum cost to make all characters equal.\n
Example 2:
\n\n\nInput: s = "010101"\nOutput: 9\nExplanation: Apply the first operation with i = 2 to obtain s = "101101" for a cost of 3.\nApply the first operation with i = 1 to obtain s = "011101" for a cost of 2. \nApply the first operation with i = 0 to obtain s = "111101" for a cost of 1. \nApply the second operation with i = 4 to obtain s = "111110" for a cost of 2.\nApply the second operation with i = 5 to obtain s = "111111" for a cost of 1. \nThe total cost to make all characters equal is 9. It can be shown that 9 is the minimum cost to make all characters equal.\n\n\n
\n
Constraints:
\n\n1 <= s.length == n <= 105s[i] is either '0' or '1'Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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