There is a special kind of apple tree that grows apples every day for n days. On the ith day, the tree grows apples[i] apples that will rot after days[i] days, that is on day i + days[i] the apples will be rotten and cannot be eaten. On some days, the apple tree does not grow any apples, which are denoted by apples[i] == 0 and days[i] == 0.
You decided to eat at most one apple a day (to keep the doctors away). Note that you can keep eating after the first n days.
Given two integer arrays days and apples of length n, return the maximum number of apples you can eat.
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Example 1:
\n\n\nInput: apples = [1,2,3,5,2], days = [3,2,1,4,2]\nOutput: 7\nExplanation: You can eat 7 apples:\n- On the first day, you eat an apple that grew on the first day.\n- On the second day, you eat an apple that grew on the second day.\n- On the third day, you eat an apple that grew on the second day. After this day, the apples that grew on the third day rot.\n- On the fourth to the seventh days, you eat apples that grew on the fourth day.\n\n\n
Example 2:
\n\n\nInput: apples = [3,0,0,0,0,2], days = [3,0,0,0,0,2]\nOutput: 5\nExplanation: You can eat 5 apples:\n- On the first to the third day you eat apples that grew on the first day.\n- Do nothing on the fouth and fifth days.\n- On the sixth and seventh days you eat apples that grew on the sixth day.\n\n\n
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Constraints:
\n\nn == apples.length == days.length1 <= n <= 2 * 1040 <= apples[i], days[i] <= 2 * 104days[i] = 0 if and only if apples[i] = 0.Compiled with clang 11 using the latest C++ 20 standard.
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