You are given a 0-indexed 2D integer array items of length n and an integer k.
items[i] = [profiti, categoryi], where profiti and categoryi denote the profit and category of the ith item respectively.
Let's define the elegance of a subsequence of items as total_profit + distinct_categories2, where total_profit is the sum of all profits in the subsequence, and distinct_categories is the number of distinct categories from all the categories in the selected subsequence.
Your task is to find the maximum elegance from all subsequences of size k in items.
Return an integer denoting the maximum elegance of a subsequence of items with size exactly k.
Note: A subsequence of an array is a new array generated from the original array by deleting some elements (possibly none) without changing the remaining elements' relative order.
\n\n\n
Example 1:
\n\n\nInput: items = [[3,2],[5,1],[10,1]], k = 2\nOutput: 17\nExplanation: In this example, we have to select a subsequence of size 2.\nWe can select items[0] = [3,2] and items[2] = [10,1].\nThe total profit in this subsequence is 3 + 10 = 13, and the subsequence contains 2 distinct categories [2,1].\nHence, the elegance is 13 + 22 = 17, and we can show that it is the maximum achievable elegance. \n\n\n
Example 2:
\n\n\nInput: items = [[3,1],[3,1],[2,2],[5,3]], k = 3\nOutput: 19\nExplanation: In this example, we have to select a subsequence of size 3. \nWe can select items[0] = [3,1], items[2] = [2,2], and items[3] = [5,3]. \nThe total profit in this subsequence is 3 + 2 + 5 = 10, and the subsequence contains 3 distinct categories [1,2,3]. \nHence, the elegance is 10 + 32 = 19, and we can show that it is the maximum achievable elegance.\n\n
Example 3:
\n\n\nInput: items = [[1,1],[2,1],[3,1]], k = 3\nOutput: 7\nExplanation: In this example, we have to select a subsequence of size 3. \nWe should select all the items. \nThe total profit will be 1 + 2 + 3 = 6, and the subsequence contains 1 distinct category [1]. \nHence, the maximum elegance is 6 + 12 = 7.\n\n
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Constraints:
\n\n1 <= items.length == n <= 105items[i].length == 2items[i][0] == profitiitems[i][1] == categoryi1 <= profiti <= 1091 <= categoryi <= n 1 <= k <= nk items (the top k most profitable items). Keep track of the items as the candidate set.n - k items sorted in non-increasing order of profits, try replacing an item in the candidate set using the current item.Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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