Given a binary string s, return true if the longest contiguous segment of 1's is strictly longer than the longest contiguous segment of 0's in s, or return false otherwise.
s = "110100010" the longest continuous segment of 1s has length 2, and the longest continuous segment of 0s has length 3.Note that if there are no 0's, then the longest continuous segment of 0's is considered to have a length 0. The same applies if there is no 1's.
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Example 1:
\n\n\nInput: s = "1101"\nOutput: true\nExplanation:\nThe longest contiguous segment of 1s has length 2: "1101"\nThe longest contiguous segment of 0s has length 1: "1101"\nThe segment of 1s is longer, so return true.\n\n\n
Example 2:
\n\n\nInput: s = "111000"\nOutput: false\nExplanation:\nThe longest contiguous segment of 1s has length 3: "111000"\nThe longest contiguous segment of 0s has length 3: "111000"\nThe segment of 1s is not longer, so return false.\n\n\n
Example 3:
\n\n\nInput: s = "110100010"\nOutput: false\nExplanation:\nThe longest contiguous segment of 1s has length 2: "110100010"\nThe longest contiguous segment of 0s has length 3: "110100010"\nThe segment of 1s is not longer, so return false.\n\n\n
\n
Constraints:
\n\n1 <= s.length <= 100s[i] is either '0' or '1'.Compiled with clang 11 using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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